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3 years ago

Special relativity can be used to study an object in which frame of reference?

Physics

2 answers:

melamori03 [73]3 years ago

4 0

Answer:

B;A frame reference that has no change in velocity

Explanation:

A P E X

Tresset [83]3 years ago

3 0

Special relativity led the path for general relativity; special relativity is in a sense a special application of the rules of general relativity. While general relativity is in position to tackle all of these problems, special relativity can tackle only problems in inertial frames. Inertial frame means that the frame of reference is inot accelerating. So, we disqualify answers A and D. However, remember that moving in a circle means that there is an acceleration, the centrifugal one, even if the speed does not change. Hence C is also incorrect.
The correct answer is B, since if there is no change in velocity, the frame does not accelerate and it is inertial.

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Two uniform solid spheres of the same size, but different mass, are released from rest simultaneously at the same height on a hi

SpyIntel [72]

Answer:

options A and C

Explanation:

Since, the spheres are of same size and rotational speed of the sphere are not dependent on their masses. So, both the sphere will reach the bottom of the at the same time with the same speed. But their kinetic energies are different.

So, options A and C are correct.

4 0

2 years ago

43. A rocket sled accelerates at a rate of 49.0m/s2. Its passenger has a mass of 75.0 kg. (a) Calculate the horizontal component

lord [1]

(a) 3675 N

Assuming that the acceleration of the rocket is in the horizontal direction, we can use Newton's second law to solve this part:

$F_x = m a_x$

where

$F_x$ is the horizontal component of the force

m is the mass of the passenger

$a_x$ is the horizontal component of the acceleration

Here we have

m = 75.0 kg

$a_x = 49.0 m/s^2$

Substituting,

$F_x=(75.0)(49.0)=3675 N$

(b) 3748 N, 11.3 degrees above horizontal

In this part, we also have to take into account the forces acting along the vertical direction. In fact, the seat exerts a reaction force (R) which is equal in magnitude and opposite in direction to the weight of the passenger:

$R=mg=(75.0)(9.8)=735 N$

where we used

$g=9.8 m/s^2$ as acceleration of gravity.

So, this is the vertical component of the force exerted by the seat on the passenger:

$F_y = 735 N$

and therefore the magnitude of the net force is

$F=\sqrt{F_x^2+F_y^2}=\sqrt{3675^2+735^2}=3748 N$

And the direction is given by

$\theta = tan^{-1}(\frac{F_y}{F_x})=tan^{-1}(\frac{735}{3675})=11.3^{\circ}$

4 0

2 years ago

An object moves with constant velocity .<br><br> •1st law<br> •2nd law

denis23 [38]

Answer:

An object moves with constant velocity .

Explanation:

•2nd law

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3 years ago

How does the strong nuclear force compare with the electrostatic force in the nucleus of an atom?

sergeinik [125]

C. The strong nuclear force is only attractive and acts over shorter distances

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3 years ago

Read 2 more answers

When electrons are shared unequally a/an<br> bond is formed

givi [52]

Covalent bonds form when electrons are shared between atoms and are attracted by the nuclei of both atoms. In pure covalent bonds, the electrons are shared equally. In polar covalent bonds, the electrons are shared unequally, as one atom exerts a stronger force of attraction on the electrons than the other.

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3 years ago