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il63 [147K]
3 years ago
13

Special relativity can be used to study an object in which frame of reference?

Physics
2 answers:
melamori03 [73]3 years ago
4 0

Answer:

B;A frame reference that has no change in velocity

Explanation:

A P E X

Tresset [83]3 years ago
3 0
Special relativity led the path for general relativity; special relativity is in a sense a special application of the rules of general relativity. While general relativity is in position to tackle all of these problems, special relativity can tackle only problems in inertial frames. Inertial frame means that the frame of reference is inot accelerating. So, we disqualify answers A and D. However, remember that moving in a circle means that there is an acceleration, the centrifugal one, even if the speed does not change. Hence C is also incorrect.
The correct answer is B, since if there is no change in velocity, the frame does not accelerate and it is inertial.
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What is the correct path of sperm cells through the male reproductive system?
irakobra [83]

Answer:

What is the correct path of sperm cells through the male reproductive system?

Epididymis, seminiferous tubules, urethra, vas deferens

<u>Seminiferous tubules, epididymis, vas deferens, urethra </u>

Urethra, seminiferous tubules, epididymis, vas deferens

Seminiferous tubules, vas deferens, epididymis, urethra

Hope this helps :)

Have a great day !

5INGH

Explanation:

8 0
2 years ago
A circular wire loop of radius 15.0 cm carries a current of 2.60
Korolek [52]
Part (a): Magnetic dipole moment

Magnetic dipole moment = IA, I = Current, A = Area of the loop
Then,
Magnetic dipole moment = 2.6*π*0.15^2 = 0.184 Am^2

Part (b): Torque acting on the loop
T = IAB SinФ, where B = Magnetic field, Ф = Angle
Then,
T = Magnetic dipole moment*B*SinФ = 0.184*12*Sin 41 = 1.447 Nm
5 0
3 years ago
A projectile is launched into the air with the initial speed of vi = 40 m/s at a launch angle of 20 degrees above the horizontal
Sphinxa [80]

The range of the projectile is 188 m

Explanation:

The motion of the arrow in this problem is a projectile motion, so it follows a parabolic path which consists of two independent motions:  

- A uniform motion (constant velocity) along the horizontal direction  

- An accelerated motion with constant acceleration (acceleration of gravity) in the vertical direction  

The path of a projectile is the combination of these two motions: see figure in attachment.

In order to find the horizontal range of the projectile, we just need to calculate the horizontal distance travelled.

We have:

t = 5.0 s (time of fligth of the projectile)

and the horizontal velocity is constant, and it is given by

v_x = v_i cos \theta

where

v_i = 40 m/s is the initial velocity

\theta=20^{\circ} is the angle of projection

Substituting,

v_x = (40)(cos 20^{\circ})=37.6 m/s

And therefore, the range of the projectile is:

d=v_x t = (37.6)(5.0)=188 m

Learn more about projectile motion:

brainly.com/question/8751410

#LearnwithBrainly

5 0
3 years ago
What is the range of a ball thrown horizontally at 12 m/s if its time of flight is 3.0 s?
vladimir1956 [14]

Answer:

6

Explanation:

because I did this assignment, :) your welcome

Next time do it by yourself, but here's the answer kid

7 0
3 years ago
Read 2 more answers
Answer the question fast please​
AnnZ [28]

Answer:

1

Explanation:

d = m \div v  \\ m = 0.8 \: v = 80\% \: also \: 0.8 \\ d = 0.8 \div 0.8 \\ d = 1

6 0
3 years ago
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