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miv72 [106K]
3 years ago
15

The technological challenges of installing cellphones across the globe

Physics
1 answer:
Leona [35]3 years ago
3 0

Answer:

I don't know sorry For this question

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Can you explain this a bit more I don’t quite understand
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2 years ago
Which factors can change the size of the shadow of an opaque object
il63 [147K]

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it have two answers a and c

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A charge of q= +15 uC moves in a Northeast direction with a speed 5 m/s, 25 degrees East of a magnetic field, pointing North, wi
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Explanation:

It is given that,

Magnitude of charge, q=15\ \mu C=15\times 10^{-6}\ C

It moves in northeast direction with a speed of 5 m/s, 25 degrees East of a magnetic field.

Magnetic field, B=0.08\ j

Velocity, v=(5\ cos25)i+(5\ sin25)j

v=[(4.53)i+(2.11)j]\ m/s

We need to find the magnitude of force on the charge. Magnetic force is given by :

F=q(v\times B)

F=15\times 10^{-6}[(4.53i+2.11j)\times 0.08\ j]

<em>Since</em>, i\times j=k\ and\ j\times j=0

F=15\times 10^{-6}[(4.53i)\times (0.08)\ j]

F=0.00000543\ kN

F=5.43\times 10^{-6}\ kN

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6 0
3 years ago
At its closest point, Mercury is approximately 46 million kilometers from the sun. What is this distance in AU?
alina1380 [7]
1 astronomical unit 1 AU = 1.4960 * 10^11 meters
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Radar waves are the waves with the lowest energy.
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