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ladessa [460]
3 years ago
9

Pls someone help 10points!!!

Physics
1 answer:
GREYUIT [131]3 years ago
3 0

Answer:

it is 45

Explanation:

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In which task is a camera the most useful?
kupik [55]

Answer:

B, to predict star count

Explanation:

the rest can be done with rulers, Einstein cans and public surveys, we can't predict how many stars there will be, but we can take pictures of them instead

8 0
3 years ago
A heat engine extracts 42. 53 kj from the hot reservior and exhausts 17. 69 kj into the cold reservior. what is the work done?
ludmilkaskok [199]

The answer is  24.84kJ.

We apply the expression for the work done by the heat engine is,

W=E_{i n}-E_{o u t}. Putting all given values in the equation we get the final answer.

What is heat engine?

  • A heat engine is a machine that uses heat to generate power. It draws heat from a reservoir, uses that heat to produce work, such as move a piston or lift weights, and then releases that heat energy into the sink.
  • We are given:The heat input is $E_{i n}=42.53 \mathrm{~kJ}$. The heat output is $E_{o u t}=17.69 \mathrm{~kJ}$.
  • The expression for the work done by the heat engine is,W=E_{i n}-E_{o u t}
  • Substituting the given values in the above expression, we will getW =42.53 \mathrm{~kJ}-17.69 \mathrm{~kJ}=24.84kJ.
  • Thus, the work done by the heat engine is 24.84kJ.

To learn more about heat engine visit: brainly.com/question/15735984

#SPJ4

6 0
2 years ago
What kind of charging occurs when you slide your body across a plastic surface?
Romashka [77]
<span>Charging by friction occurs, Electrons are transferred when one object rubs against another.

Another example of this would be socks on carpet.

Hope this helps!</span>
6 0
3 years ago
the average power of the Sun is 3.79x1026 Watts, answer the following questions: 13. What is the average intensity of light at E
Lemur [1.5K]

Explanation:

Given that,

Average power of sun P=3.79\times10^{26}\ Watt

We need to calculate the intensity of light at Earth's position

Using formula of intensity

I=\dfrac{P_{avg}}{4\pi r^2}

Where, I = intensity

P = power

Put the value into the formula

I=\dfrac{3.79\times10^{26}}{4\pi\times(1.496\times10^{11})^2}

I=1347.616\ W/m^2

So, The intensity is 1347.616 W/m².

(A). We need to calculate the pressure on a solar sail due to the light of the sun if it's fully reflective

Using formula for fully reflective

P = \dfrac{2I}{c}

Put the value into the formula

P=\dfrac{2\times1347.616}{3\times10^{8}}

P=8.984\times10^{-6}\ N/m

(B).  We need to calculate the pressure on a solar sail due to the light of the sun if it's fully reflective

Using formula for fully absorptive

P=\dfrac{I}{c}

P=\dfrac{1347.616}{3\times10^{8}}

P=4.492\times10^{-6}\ N/m

Hence, This is the required solution.

6 0
3 years ago
Time (min)
charle [14.2K]

Answer:

rgvdghrryyrfgtr was the other monkey that I have to do with my best pet peeve for the rest and neon scooter is my friend is giving her the money for your cuz to be a good offer tho it was a great idea for a while and then she said yes and she is a great person ever and she was madly happy I have to go soon to be honest with me if she wants me back to my base or not but she wasnt it to be honest with her but

8 0
3 years ago
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