Answer:
0
Explanation:
The overall charge on this atom is 0.
To find the charge on an atom;
charge = number of protons - number of electrons.
Note:
- Protons are the positively charged particles in an atom
- Electrons are the negatively charged particles in an atom
- Neutrons carries no charges on them.
Since the atom is made up of equal number of protons and electrons, the charge on it is 0.
If the number of electrons is more, the atom will be negatively charge but if the number of protons is more, it will be positively charged.
Suppose car A is moving with a velocity Va, and car b with a velocity Vb,
According the principle of conservation of momentum:
Va x Ma + Vb x Mb = (Ma + Mb) V
V = (Va x Ma + Vb x Mb)/(Ma +Mb)
V = speed of cars after coupling
V = (Va x 20 mg + Vb x 15 mg)/(20 mg + 15 mg)
Put in the values of Va and Vb, and get the V
The solution that would most likely be a strongest conductor of electricity is the solution that is most saturated or concentrated. This is because the atoms that are found within the aqueous solutions have become positively charged resulting to the attraction of negatively charged ions that are found in electricity. On the other hand, the least conductive from the aqueous solutions would be the most unsaturated one because of less conductive ions present.
Average speed = (total distance covered) / (time to cover the distance)
total distance covered = (4km + 2km + 1km) = 7 km
time to cover the distance = (32min + 22min + 16min) = 70 min
Average speed = (7 km) / (70 min)
Average speed = 0.1 km/minute
Answer:
The rock's final speed at the required altitude will be 42.24 m/s.
Explanation:
Let's start by finding the initial vertical speed.
Vertical Speed = 1.61 * Sin (53.2°)
Vertical Speed = 0.8 m/s
We want to know the speed of the rock when it is at an altitude of 91 km.
The total displacement of the rock from its starting position will thus be equal to -91 km
We can use this in the following equation:
![s=u*t+\frac{1}{2} (a*t^2)](https://tex.z-dn.net/?f=s%3Du%2At%2B%5Cfrac%7B1%7D%7B2%7D%20%28a%2At%5E2%29)
![-91=0.8*t+\frac{1}{2} (-9.8*t^2)](https://tex.z-dn.net/?f=-91%3D0.8%2At%2B%5Cfrac%7B1%7D%7B2%7D%20%28-9.8%2At%5E2%29)
t = 4.3918 seconds
Thus it takes 4.3918 seconds to reach the required altitude. We can now find the speed as follows:
![V=U+at](https://tex.z-dn.net/?f=V%3DU%2Bat)
![V=0.8+(-9.8)*(4.3918)](https://tex.z-dn.net/?f=V%3D0.8%2B%28-9.8%29%2A%284.3918%29)
![V = -42.24](https://tex.z-dn.net/?f=V%20%3D%20-42.24)
Thus the rock's final speed at the required altitude will be 42.24 m/s.