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Sonbull [250]
3 years ago
11

3. Question

Physics
2 answers:
aalyn [17]3 years ago
5 0
2. Newton's laws of motion
miskamm [114]3 years ago
5 0

Hello!

Answer: Newton's Laws of Motion.

Explanation:

↓↓↓↓↓↓↓↓↓↓↓↓

Isaac Newton he performed many experiments involving light (optics). Then he published works on mathematics, history, calculus, and theology. And he published his most significant book, Philosophiae Naturalis Principia Mathematica, in 1687. Newton's first law of motion states that an object at rest stays at rest, and an object in motion stays in motion, unless acted on by an unbalanced force. This is also known as the law of inertia. Inertia is the natural tendency of objects to resist change in motion. Newton's second law of motion states that the total net force acting an object is equal to mass times acceleration. Newton's third law of motion states that for every action, there is an equal and opposite reaction. It considered action and reaction forces.

Hope this helps!

Thank you for posting your question at here on brainly.

-Charlie

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Read 2 more answers
*please refer to photo* An electric field of magnitude 5.25 ✕ 10^5N/C points due south at a certain location. Find the magnitude
kvv77 [185]

Answer:

Approximately 3.86\; {\rm N} (given that the magnitude of this charge is -7.35\; {\rm \mu C}.)

Explanation:

If a charge of magnitude q is placed in an electric field of magnitude E, the magnitude of the electrostatic force on that charge would be F = E\, q.

The magnitude of this charge is q = 7.35\; {\rm \mu C}. Apply the unit conversion 1\; {\rm \mu C} = 10^{-6}\; {\rm C}:

\begin{aligned} q &= 7.35\; {\mu C} \times \frac{10^{-6}\; {\rm C}}{1\; {\mu C}} = 7.35\times 10^{-6}\; {\rm C}\end{aligned}.

An electric field of magnitude E = 5.25\times 10^{5}\; {\rm N \cdot C^{-1}} would exert on this charge a force with a magnitude of:

\begin{aligned}F &= E\, q \\ &= 5.25 \times 10^{5}\; {\rm N \cdot C^{-1}} \times (-7.35\times 10^{-6}\; {\rm C}) \\ &\approx 3.86\; {\rm N}\end{aligned}.

Note that the electric charge in this question is negative. Hence, electrostatic force on this charge would be opposite in direction to the the electric field. Since the electric field points due south, the electrostatic force on this charge would point due north.

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