Answer:
E= 1.968 10¹¹ N/C
Explanation:
To calculate the electric field of a sphere we can use Gaussian law
Ф = ∫ E. dA = / ε₀
In this case we must use a Gaussian surface of spherical shape, since the radii of the sphere and the electric field line have been parallel, consequently the scalar product is reduced to an algebraic product.
The error of a sphere is
A = 4π π r²
E (4π r³) = / εo (1)
to find the charge inside the sera we use the concept of density
ρ = quint / V
qint = rho V
the volume of a sphere is
V = 4/3 pi r³
we substitute in 1
E 4π r² = ρ 4/3 π r³
E = ρ / 3ε₀
now let's change the charge density to the charge
E = Q 3 / 4π r³ r / 3ε₀
E = (1 / 4πε₀) Q / r²
E = k Q /r²
calculate
E = ρr / 3ε₀
E = 6.7 10⁻⁹ 7.8 10⁻² / 3 8.85 10⁻¹²
E= 1.968 10¹¹ N/C
Answer:
Explanation:
From the question we are told that:
Pressure of
Bottle cap area
Generally the equation for Resultant pressure is give as is mathematically given by
Where
Generally the equation for Force exerted by screw F is give as is mathematically given by