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Tems11 [23]
2 years ago
13

How do defined terms and undefined terms relate to each other ?

Mathematics
1 answer:
dalvyx [7]2 years ago
7 0
<span>In geometry, definitions are formed using known words or terms to describe a new word. There are three words in geometry that are not formally defined. These three undefined terms are point, line and plane. Undefined terms have not been defined, and defined are answered. They are terms that have a relationship with the point od discussion. :)</span>
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Please help me. i want to have this finished.
Anuta_ua [19.1K]
We know that y is equal to x-2. We can just substitute x-2 for y since y is equal to it. 

10x- 9(x-2)=24

Distribute.

10x- 9x+18= 24

x+18= 24

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x= 6

Now, plug in x.

y= (6)-2

y= 4

We can check this to see if this works:

4= 6-2, 4=4 

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5 0
3 years ago
Ben and his three friends were ordering pizza. They could spend at most $26. If a large
lutik1710 [3]

Answer:

6 toppings

Step-by-step explanation:

The t in this equation represents the amount of toppings.

22 + 0.65t = 26

-22 -22

0.65t = 4

0.65t/0.65 = 4/0.65

t = 6

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6 0
3 years ago
Se tiene un rectángulo cuya base mide el doble que su altura y su área es 12
irina [24]

Answer:

Part 1) The perimeter is  P=6\sqrt{6}\ cm

Part 2) The diagonal is d=\sqrt{30}\ cm

Step-by-step explanation:

<u><em>The question in English is</em></u>

You have a rectangle whose base is twice the height and its area is 12

square centimeters. Calculate the perimeter of the rectangle and its diagonal

step 1

Find the dimensions of rectangle

we know that

The area of rectangle is equal to

A=bh

A=12\ cm^2

so

bh=12 ----> equation A

The base is twice the height

so

b=2h ----> equation B

substitute equation B in equation A

(2h)h=12\\2h^2=12\\h^2=6\\h=\sqrt{6}\ cm

Find the value of b

b=2\sqrt{6}\ cm

step 2

Find the perimeter of rectangle

The perimeter is given by

P=2(b+h)

substitute

P=2(2\sqrt{6}+\sqrt{6})\\P=6\sqrt{6}\ cm

step 3

Find the diagonal of rectangle

Applying the Pythagorean Theorem

d^2=b^2+h^2

substitute

d^2=(2\sqrt{6})^2+(\sqrt{6})^2

d^2=30

d=\sqrt{30}\ cm

3 0
3 years ago
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