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Tems11 [23]
3 years ago
13

How do defined terms and undefined terms relate to each other ?

Mathematics
1 answer:
dalvyx [7]3 years ago
7 0
<span>In geometry, definitions are formed using known words or terms to describe a new word. There are three words in geometry that are not formally defined. These three undefined terms are point, line and plane. Undefined terms have not been defined, and defined are answered. They are terms that have a relationship with the point od discussion. :)</span>
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What is the measure of AC ? Enter your answer in the box.
andrezito [222]
To solve for AC in the given inscribed angle we proceed as follows:
An inscribed angle is an angle with its vertex "on" the circle formed by two intersecting chords as in our drawing. Thus here we shall use the formula:
Inscribed Angle=1/2 intercepted Arc
thus
m∠ABC=1/2mAC
thus plugging in our values we shall have:
4x-3.5=1/2(4x+17)
4x-3.5=2x+8.5
solving simplifying and solving for x we obtain
4x-2x=8.5+3.5
2x=12
hence
x=12/2
x=6°
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Answer:

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Step-by-step explanation:

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Which expression is equal to<br> 5, ?<br> A<br> 542<br> B.<br> 51<br> Cw<br> D.<br> 254
nirvana33 [79]

Answer:

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3 years ago
WILLL GIVE POINTS
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Answer:

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A 150 no container can hold 23.6 g of aluminum what is the density of the aluminum?
Drupady [299]

Answer:

# The density of the aluminum is 59/375 ≅ 0.157 g/cm³

# The volume of the container is 4/17 ≅ 0.235 cm³

# The mass of iron is 1225 g

Step-by-step explanation:

* Lets explain how to solve the problem

- Density is a measurement that compares the amount of matter

 of an object to its volume [ Density = mass/volume]

- Density is found by dividing the mass of an object by its volume

- The unit of measuring density is gram per centimeter³ (milliliter)

* Lets solve the problems

# A container of volume 150 cm³ can hold 23.6 g of aluminum

∵ Density = mass/volume

∵ The mass = 23.6 g

∵ The volume = 150 cm³

∴ The density = 23.6/150 = 59/375 ≅ 0.157 g/cm³

* The density of the aluminum is 59/375 ≅ 0.157 g/cm³

# The density of mercury is 13.6 g/cm³ at 23 C°

- A container can hold 3.2 g of mercury at this temperature

∵ Density = mass/volume

∵ The mass = 3.2 g

∵ The density = 13.6 g/cm³

∴ 13.6 = 3.2/volume

- By using cross multiplication

∴ The volume = 3.2/13.6 = 4/17 cm³

* The volume of the container is 4/17 ≅ 0.235 cm³

# The density of the iron is 4.9 g/cm³

- The beaker has a volume 250 ml

∵ Density = mass/volume

∵ The ml = cm³

∴ The volume of the beaker is 250 cm³

∵ The density = 4.9 g/cm³

∴ 4.9 = mass/250

- Multiply both sides by 250

∴ mass = 1225 g

* The mass of iron is 1225 g

7 0
3 years ago
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