Question

The dimensions of a box are as follows:

Answer 1

Answer:

Part 1: V = (x + 2)(x)(3x)

Part 2: V = 3x³ + 6x²

Part 3: A = 2[x(x + 2) + 3x(x + 2) + 3x(x)]

Part 4: A = 14x² + 16x

Step-by-step explanation:

The box has

Width  = x,

Length = x + 2

Height  = 3x

Part 1:

Volume of the box is given by, V = Length × Width × Height

⇒ V = (x + 2)(x)(3x) ....... (1) (Answer)

Part 2:

Hencem we can write from the equation (1)

V =  3x²(x + 2) = 3x³ + 6x² (Answer)

Part 3:

Totall surface area of the box is given by

sa = 2(wl + hl + hw)

⇒ A = 2[x(x + 2) + 3x(x + 2) + 3x(x)] ........ (2) (Answer)

Part 4:

So, from equation (2) we get,

A = 2[x² + 2x + 3x² + 6x + 3x²]

⇒ A = 14x² + 16x (Answer)