A.) 3 H2SO4 + 2 Al > Al2(SO4)3 + 3 H2
6 H+ +3 S +12 O +2 Al> 2 Al + 3S + 12O + 6H+
This one is balanced, with 6 H, 3 S, 12 O, and 2 Al on both sides.
B.) 2KCl + Pb(NO3)2 > KNO3 + PbCl2
2K + 2Cl + Pb + 2N +6 O > 1 K + 1 N+ 3 O + Pb + 2 Cl
This one is not balanced as there is 2 K, 6 O and 2 N on the reactants side but only 1 K, 3 O, and 1 N on the products side.
Therefore, only A.) is balanced
When we have Avogadro's number with four significant figures 6.022 x 10^23
and we have also this number 2.055 is also with four significant figures so,
the number of atoms = Avogadro's number / 2.055
= 6.022 x 10^23 / 2.055
= 2.930 x 10^23
and we can see that the result is number with four significant figures
Answer:
Option A. Double Replacement
Explanation:
A double displacement reaction is a kind of reaction in which there is an exchange of the ions of the two reactants to form a different products. In the equation, K in KOH displaces H in H3PO4 to form K3PO4 and also, the H combines with OH to form water.
H3PO4+3KOH -> K3PO4+3H20
Answer:
Mass of ammonia = 34 g
Explanation:
Given data:
Number of molecules of ammonia = 1.204 × 10²⁴
Mass of ammonia = ?
Solution:
First of all we will calculate the number of moles.
one mole of ammonia = 6.022 × 10²³ molecules
n = 1 mole/6.022 × 10²³ molecules × 1.204 × 10²⁴ molecules
Number of moles = 2 mol
Mass of ammonia:
Number of moles = Mass / molar mass
Mass of ammonia = number of moles × molar mass
Mass of ammonia = 2 mol × 17 g/mol
Mass of ammonia = 34 g