Answer:
10.88 g
Explanation:
We have:
[CH₃COOH] = 0.10 M
pH = 5.25
Ka = 1.80x10⁻⁵
V = 250.0 mL = 0.250 L
The pH of the buffer solution is:
(1)
By solving equation (1) for [CH₃COONa*3H₂O] we have:
Hence, the mass of the sodium acetate tri-hydrate is:
Therefore, the number of grams of CH₃COONa*3H₂O needed to make an acetic acid/sodium acetate tri-hydrate buffer solution is 10.88 g.
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Answer: 5. Determine the number of atoms that are in 0.58 mol of Se. 0.58molo se x 6.02x1020 g tors Se - 3.5X1023 atoms Se 1 mol of Se 6.
Explanation:
Answer:
0.3 moles /liter
Explanation:
The molar mass of Fe(NO3)3.9H2O is 403.99
40.4 g of Fe(NO3)3.9H2O is approximately equivalent to 40.4/404.4 = 0.1 moles
As each unit of the hydrated iron nitrate contributes one unit of iron(3) ions, the concentration of iron(3) ions in the solution is 0.1 moles/liter.
As each unit of the hydrated iron nitrate contributes 3 units of nitrate ions, the concentration of nitrate ions if 0.3 moles/liter.
<span>The answer is 1. Copper is an element with sign Cu and atomic number 29 which means that there are 29 protons in this element. It is a soft, flexible, and elastic metal with very extraordinary thermal and electrical conductivity. A newly unprotected exterior of pure copper has a reddish-orange color. </span>
Answer:
5-methylhex-1-yne//5-methylhex-2-yne//2-methylhex-3-yne
Explanation:
We have to start with the information on the <u>IR spectrum</u>. The signal at 3300 is due to a <u>C-H bend sp carbon</u> and the signal in 2200 is due to the <u>stretch carbon-carbon</u>. Therefore we will have an alkyne. Now if we have 2-methylhexane as the product of hydrogenation we have <u>several options to put the triple bond</u>. Between carbons 1 and 2 (5-methylhex-1-yne), between carbons 2 and 3 (5-methylhex-2-yne) and between carbons 3 and 4 (2-methylhex-3-yne). On carbon 5 we have a tertiary carbon therefore we dont have any other options.
See figure 1
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