Answer:
Probability that component 4 works given that the system is functioning = 0.434 .
Step-by-step explanation:
We are given that a parallel system functions whenever at least one of its components works.
There are parallel system of 5 components and each component works independently with probability 0.4 .
Let <em>A = Probability of component 4 working properly, P(A) = 0.4 .</em>
<em>Also let S = Probability that system is functioning for whole 5 components, P(S)</em>
Now, the conditional probability that component 4 works given that the system is functioning is given by P(A/S) ;
P(A/S) = {Means P(component 4 working and system also working)
divided by P(system is functioning)}
P(A/S) = {In numerator it is P(component 4 working) and in
denominator it is P(system working) = 1 - P(system is not working)}
Since we know that P(system not working) means that none of the components is working in system and it is given with the probability of 0.6 and since there are total of 5 components so P(system working) = 1 -
.
Hence, P(A/S) =
= 0.434.
Answer:
141
Step-by-step explanation:
1. The volume of a cylinder is
, where r = radius and h = height. In this case, the height is 5 feet and the radius is 3 feet.
Solving Volume
Step 1: Plug in values
Step 2: Simplify.
Therefore, the volume of the cylinder is 141 ft^3 (but don't put ft^3, as mentioned in the problem).
Have a lovely rest of your day/night, and good luck with your assignments! ♡
Answer:
The value of A is 5
Step-by-step explanation:
- The number is divisible by 3 if the sum of its digits is a number
divisible by 3
- Ex: 126 is divisible by 3 because the sum of its digits = 1 + 2 + 3 = 6
and 6 is divisible by 3
- The number is divisible by 5 if its ones digit is zero or 5
- Ex: 675 is divisible by 5 because its ones digit is 5
890 is divisible by 5 because its ones digit is 0
- We are looking for the value of A in the 4-digit number 3A5A which
makes the number divisible by both 3 and 5
∵ A is in the ones position
∴ A must be zero or 5
- Let us try A = 0
∵ A = 0
∴ The number is 3050
∵ The sum of the digits of the number = 3 + 0 + 5 + 0 = 8
∵ 8 is not divisible by 3
∴ 3050 is not divisible by both 3 and 5
∴ A can not be zero
- Let us try A = 5
∵ A = 5
∴ The number is 3555
∵ The sum of the digits of the number = 3 + 5 + 5 + 5 = 18
∵ 18 is divisible by 3
∴ 3555 is divisible by both 3 and 5
∴ A must be equal 5
* <em>The value of A is 5</em>
Because the tell if he number is big or small