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Gelneren [198K]
3 years ago
8

What is the difference between plotting (2, 3) and (3, 2) on a coordinate plane? Explain

Mathematics
2 answers:
JulijaS [17]3 years ago
8 0
Because you have your X value which would be 2 in (2,3) and 3 in (3,2) and your y value which is 3 in (2,3) and 2 in (3,2) so what you would have to do in order to graph 2,3 you would go over right 2 and up 3. but in 3,2 you would go over 3 and up two.
Hope this helped

SOVA2 [1]3 years ago
7 0
The first number will be how far you go on the X axis, so the first will move 2 to the right of the origin(origin is 0,0) and the second will move 3 to the right o the origin. Next you have the run which is the second value and controls where the point goes on the y axis. The first will move three up AFTER moving two to the right and the second will move 2 up AFTER moving 3 to the right. They have different x and y values. ( a point will be shown in the form of x,y)
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Find the prime factorization of the number 20. If the number is prime, state this
mihalych1998 [28]

Answer:

Some of the prime factors are 1,2,4,5,10,20,-1,-.2,-4,-5,-10,-20, and since 5 is prime you can just start with 5 and 4

Step-by-step explanation:

3 0
3 years ago
Please help me please I don’t understand and my teacher said I got it wrong for numbers 1 2 and 3
kirza4 [7]

Answer:

1) 5/9

2) 4/7

3) 3/8

Step-by-step explanation:

1) 5/9

2) 4/7

3)3/8

3 0
3 years ago
Read 2 more answers
If a bus driver get paid $20,000 a year and he works 35 weeks a year how many weeks will it take for him to earn $2000
alexgriva [62]

Answer:

3.5?

Step-by-step explanation:

2,000 is 10% of 20,000

3.5 is 10% of 35



7 0
3 years ago
Read 2 more answers
Can someone pls help??
Vlad1618 [11]

Answer:

a. The y coordinates for A are either 10 or -14

b.  The y coordinates for A are either -11 or 7

Step-by-step explanation:

distance = sqrt ((x2-x1)^2+(y2-y1)^2)

We know Point B and the x coordinate of point A as well as the distance

15 = sqrt ((-4-5)^2+(-2-y1)^2)

15 = sqrt ((-9)^2+(-2-y1)^2)

15 = sqrt (81+(-2-y1)^2)

Square each side

15^2 =sqrt (81+(-2-y1)^2)^2

225 =  81+(-2-y1)^2

Subtract 81 from each side

225-81 = 81-81 +(-2-y1)^2

144 = (-2-y1)^2

Take the square root of each side

±sqrt 144 = sqrt(-2-y1)^2

±12 = (-2-y1)

Add 2 to each side

2±12 = 2-2-y1

2±12 = -y1

14 = -y1  or -10 = -y1

Multiply by -1

-14 = y1  or 10 = y1

The y coordinates for A are either 10 or -14

Now move B to -7,-2

15 = sqrt ((-7-5)^2+(-2-y1)^2)

15 = sqrt ((-12)^2+(-2-y1)^2)

15 = sqrt (144+(-2-y1)^2)

Square each side

15^2 =sqrt (144+(-2-y1)^2)^2

225 =  144+(-2-y1)^2

Subtract 144 from each side

225-144 = 144-144 +(-2-y1)^2

81 = (-2-y1)^2

Take the square root of each side

±sqrt 81 = sqrt(-2-y1)^2

±9 = (-2-y1)

Add 2 to each side

2±9 = 2-2-y1

2±9 = -y1

11 = -y1  or -7 = -y1

Multiply by -1

-11 = y1  or 7 = y1

The y coordinates for A are either -11 or 7

3 0
3 years ago
3x - 1/5= x+1/3 Could you please solve this as soon as possible
VARVARA [1.3K]

x = 0.27

:)

good luck

4 0
4 years ago
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