What is the measure of each exterior angle of a regular polygon with 12 sides?

1 answer:

8 0

A polygon has as many interior angles as sides. An equilateral triangle has three equal 60 degree angles. The sum of the angles of this and any triangle is 180 degrees.The sum of the four interior angles of a square is 360 degrees, which is the same for any quadrilateral.

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Help middle school question!!!

Sav [38]

Answer:

The shaded region has an area of 1400 square units

Step-by-step explanation:

Area of Compound Shapes

We are given a shape and it's required to calculate its area. The shape can be divided into three rectangles as shown in the figure attached below.

The lengths of these rectangles are x, y, and z.

The value of x can be calculated as:

x = 60 - 15 - 10 = 35

Similarly:

y = 60 - 15 = 45

z = y = 45

The first rectangle has dimensions of x by 10, thus its area is:

A1 = 35*10 = 350

The second rectangle has dimensions of 60 by 10:

A2 = 60*10 = 600

The third rectangle has dimensions y by 10:

A3 = 55*10 = 450

The shaded area is:

A = 350 + 600 + 450 = 1400

The shaded region has an area of 1400 square units

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2 years ago

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(ED. 21) Analytic Geometry Unit Test..... #3 Which point is a solution of x2 + y2 > 49 and y ≤ –x2 – 4?

sdas [7]

Answer:

We want to find a solution of the system:

x^2 + y^2 > 49

y ≤ –x^2 – 4

Here we do not have any options, so let's try to find a general solution.

First, we can remember that the equation of a circle centered in the point (a, b) and of radius R is:

(x - a)^2 + (y - b)^2 = R^2

If we look at our first inequality, we can write it as:

x^2 + y^2 > 7^2

So the solutions of the first inequality are all the points that are outside (because the symbol used is >) of the circle of radius R = 7 centered in the origin.

From the other equation, we would get:

y ≤ –x^2 – 4

This is parabola, anything that is in the graph of the parabola or below will be a solution for this inequality.

Then the solutions of the system, are the ones that are in the region of solutions for both inequalities.

You can see the graph below, where both regions are graphed. The intersection of these regions is the region of the solutions for the system of inequalities:

by looking at the graph, we can see a lot of points that are solutions, like:

(0, -10)

(0, -15)

(2, -10)

etc.