There should be 22 figures .
Answer:
72.2 ml
Explanation:
The neutralization equation between HBr (acid) and NaOH (base) is the following:
HBr(aq) + NaOH(aq) → NaBr(aq) + H₂O(l)
We can see that 1 mol of HBr reacts with 1 mol of NaOH. At the equivalence point, the total number of moles of HBr reacts with the total number of moles of NaOH. The number of moles can be calculated as the product between the molarity (M, in mol/L) and the volume (V). So, we can equal the quantities of acid and base, as follows:
moles HBr = moles NaOH
M(HBr) x V(HBr) = M(NaOH) x V(NaOH)
Now, we calculate the volume of NaOH with the data:
V(NaOH)= M(HBr) x V(HBr)/M(NaOH)
= (2.60 mol/L x 50.0 ml)/(1.80 mol/L)
=72.2 ml
Answer:
The correct answer is 89.6 L
Explanation:
We have the following chemical equation and the molar masses for the reaction:
3H₂(g) + N₂ --> 2 NH₃
6 g 28 g 34 g
That means that 3 moles of H₂ (6 g) reacts with 1 mol of N₂ (28 g) and gives 2 moles of NH₃ (34 g). In order to calculate how many liters of NH₃ result from the reaction of 12 grams of H₂ and 28 grams of N₂, we have to first figure out which reactant is the <em>limiting reactant</em>. According to the equation, if 6 grams of H₂ reacts with 28 g of N₂, and we have 12 grams:
6 g H₂------- 28 g N₂
12 g H₂-------- X = 12 g H₂ x 28 g N₂/6 g H₂ = 56 g N₂
We need 56 g of N₂ but we have 28 g of N₂, so <em>N₂ is the limiting reactant</em>. With the limiting reactant we can calculate the moles of product (NH₃) we will obtain:
We have 28 g N₂ -----> 28 g/14 g/mol = 2 moles N₂
1 mol N₂ ----------- 2 moles NH₃
2 mol N₂ --------- X = 2 mol N₂ x 2 moles NH₃/1 mol N₂ = 4 mol NH₃
Finally, we convert the moles of NH₃ to liters:
1 mol gas at STP = 22.4 L
Liters NH₃ obtained = 4 moles NH₃ x 22.4 L/1 mol = 89.6 L
Answer:
13.3 h
Explanation:
Step 1: Given data
Time (t): 48,000 seconds
Step 2: Convert "t" from seconds to minutes
We will use the conversion factor 1 min = 60 s.
48,000 s × 1 min/60 s = 800 min
Step 3: Convert "t" from minutes to hours
We will use the conversion factor 1 h = 60 min.
800 min × 1 h/60 min = 13.3 h
To sum up, 48,000 seconds is equal to 13.3 hours.
Answer:
3.011 × 10²³ particles
Explanation:
Given data:
Number of moles = 0.5 mol
Number of particles = ?
Solution:
The given problem will solve by using Avogadro number.
It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.
The number 6.022 × 10²³ is called Avogadro number.
one mole of substance = 6.022 × 10²³ particles
For 0.5 mole of substance:
0.5 mol × 6.022 × 10²³ particles / 1 mol
3.011 × 10²³ particles