<span>some elements would be Beryllium, Barium, Magnesium, and Strontium</span>
The correct answer is BeCl_2(l)+2Cl^-(solvated)→BeCl_4^2-.
Evaluating be behavior to see :
how it differs from the other Group 2A (2) members.
In this reaction Be behaves like other alkaline earth metals
The complete equation can be given as
BeCl_2(l)+2Cl^-(solvated)→BeCl_4^2-
BeCl_2 tends to form a chloro bridged dimer in the vapour state, however at high temperatures of the order of 1200K, this dimer dissociates into the linear monomer.
BeCl_2 has a chain structure in its solid form. Each Be atom in this structure is surrounded by chlorine atoms, two of which are connected by conversion bonds and the remaining two by covalent coordinate connections. This chain structure is displayed.
To know more about BeCl₂(I) + Cl⁻ refer the link:
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Answer:
Your notation is a bit confusing, let me write it more clearly.
Explanation:
( Temperature in °F − 32) × 5/9 = Temperature in °C
At room temperature, water is liquid in form. For helium, it is gas because it is the second lightest element in nature. So, you would expect the density of Helium to be much less than 1 g/cm³. Because gas is very light and occupies a lot of space, the density would result to a very small number.
