All categories

3 years ago

You download 12 new songs to your MP3 player. then you delete 5 old songs.Write each amount as an interger

Mathematics

1 answer:

ASHA 777 [7]3 years ago

3 0

Given statement is "You download 12 new songs to your MP3 player. then you delete 5 old songs."

We have to write each amount as an integer.

Download 12 new songs means you are adding number to your MP3 player so we will use + sign for 12

So the amount in integer form will be +12

Ddelete 5 old songs means you are subtracting number from your MP3 player so we will use - sign for 5

So the amount in integer form will be -5

combining both expressions we can write final statement as:

+12-5

Which can be simplified to +7.

You might be interested in

Neveah orders a square pizza. 34 34 of the pizza has pepperoni. 23 23 of the pepperoni also has green peppers. How much of the w

astra-53 [7]

Answer:

1/2

Step-by-step explanation:

Given that:

3/4 of pizza has pepperoni

2/3 of the pizza with pepperoni has green pepper ;

The fraction of the whole pizza that has both pepperoni and green pepper ;

Fraction with pepperoni = 3/4

Fraction of whole with green pepper and pepperoni : 2/3 of 3/4 = 2/3 * 3/4 = (2*3) / (3*4) = 6/12 = 1/2

8 0

3 years ago

Graph the inequality x plus y is equal to or greater than -4

Setler [38]

Answer:

Step-by-step explanation:

x+y≥-4

consider x+y=-4

when x=0,y=-4

point is (0,-4)

when y=0,x=-4

point is (-4,0)

draw a line through (0,-4) and (-4,0)

put x=0,y=0

0+0≥-4

which is true.

Hence origin lies on the graph.

graph is on and right of the line.

4 0

4 years ago

Random samples of size 49 are taken from a population that has 200 elements, a mean of 180, and a variance of 196. the distribut

OleMash [197]

Answer:

The mean is 180.

The standard error is 0.286.

Step-by-step explanation:

This question can be solved using the central limit theorem.

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $\frac{\sigma}{\sqrt{n}}$ .