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Levart [38]
3 years ago
6

As SCUBA divers go deeper underwater, the pressure from the weight of all the water above them increases tremendously which comp

resses the gases in their blood. What happens to the volume of gas in their blood as the diver rises quickly to the surface?
A.
As a diver rises, the pressure on their body decreases which allows the volume of the gas to decrease.

B.
As a diver rises, the pressure on their body increases which allows the volume of the gas to decrease.

C.
As a diver rises, the pressure on their body decreases which allows the volume of the gas to increase.

D.
As a diver rises, the pressure on their body increases which allows the volume of the gas to increase.
Physics
1 answer:
slavikrds [6]3 years ago
4 0

Answer: A.

As a diver rises, the pressure on their body decreases which allows the volume of the gas to decrease.

Explanation:

The problem is that a diver, experiences an increased pressure of water compresses nitrogen and more of it dissolves into the body. Just as there is a natural nitrogen saturation point at the surface, there are saturation points under water. Those depend on the depth, the type of body tissue involved, and also how long a diver is exposed to the extra pressure. The deeper a diver go, the more nitrogen the body absorbs.

The problem is getting rid of the nitrogen once you ascend again. As the pressure diminishes, nitrogen starts dissolving out of the tissues of the diver's body, a process called "off-gassing." That results in tiny nitrogen bubbles that then get carried to the lungs and breathed out. However, if there is too much nitrogen and/or it is released too quickly, small bubbles can combine to form larger bubbles, and those can do damage to the body, anything from minor discomforts all the way to major problems and even death.

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A hot-air balloon is ascending at the rate of 10 m/s and is 74 m above the ground when a package is dropped over the side. (a) H
Reika [66]

Answer:

The answer to your question is:

a)  t1 = 2.99 s ≈ 3 s

b)  vf = 39.43 m/s

Explanation:

Data

vo = 10 m/s

h = 74 m

g = 9.81 m/s

t = ?   time to reach the ground

vf = ?   final speed

a)    h = vot + (1/2)gt²

     74 = 10t + (1/2)9.81t²

     4.9t² + 10t -74 = 0                  solve by using quadratic formula

   

   t = (-b ± √ (b² -4ac) / 2a

   t = (-10 ± √ (10² -4(4.9(-74) / 2(4.9)

   t = (-10 ± √ 1550.4 ) / 9.81

  t1 = (-10 + √ 1550.4 ) / 9.81               t2 = (-10 - √ 1550.4 ) / 9.81

  t1 = (-10 ± 39.38 ) / 9.81                    t2 = (-10 - 39.38) / 9.81

   t1 = 2.99 s ≈ 3 s                               t2 = is negative then is wrong there are

                                                                   no negative times.

b) Formula vf = vo + gt

                  vf = 10 + (9.81)(3)

                  vf = 10 + 29.43

                  vf = 39.43 m/s

4 0
3 years ago
Object A has 25 J of kinetic energy. Object B has one-quarter the mass of object A.By what factor does the speed of each object
Natalka [10]

Answer:

The speed of object B is 2 times of speed of object A.

Explanation:

Given that,

Kinetic energy of object A = 25 J

Mass of object B m_{B}=\dfrac{1}{4}m_{A}

Work done = -20 J

We need to calculate the factor of the speed of the object

Suppose the final kinetic energy is same for both object.

K.E_{f_{A}}=K.E_{f_{B}}

\dfrac{1}{2}m_{A}v_{A}^2=\dfrac{1}{2}m_{B}v_{B}^2

Put the value into the formula

\dfrac{1}{2}m_{A}\times v_{A}^2=\dfrac{1}{2}\times\dfrac{1}{4}m_{A}\times v_{B}^2

\dfrac{v_{A}}{v_{B}}=\dfrac{1}{2}

v_{A}=\dfrac{1}{2}v_{B}

v_{B}=2v_{A}

Hence, The speed of object B is 2 times of speed of object A.

4 0
3 years ago
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In an electromagnetics lab, you are studying two coils which have a mutual inductance of M=300 mH. Suppose that the current in t
Firdavs [7]

Answer:

Explanation:

Given that,

The mutual inductance of the two coils is

M = 300mH = 300 × 10^-3 H

M = 0.3 H

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∆I = I_2 - I_1 = 10 - 2.8

∆I = 7.2 A

Within the time 300ms

t = 300ms = 300 × 10^-3

t = 0.3s

Second Coil resistance

R_2 = 0.4 ohms

We want to find the current in the second coil,

The same induced EMF is in both coils, so let find the EMF,

From faradays law

ε = Mdi/dt

ε = M•∆I / ∆t

ε = 0.3 × 7.2 / 0.3

ε = 7.2 Volts

Now, this is the voltage across both coils,

Applying ohms law to the second coil, V=IR

ε = I_2•R_2

0.72 = I_2 • 0.4

I_2 = 0.72 / 0.4

I_2 = 1.8 Amps

The current in the second coil is 1.8A

7 0
3 years ago
Elements known as noble gases do not have the ability or the room in their valence
Eva8 [605]

Answer:

true

Explanation:

noble gases are octet meaning they they have eight electrons in their outer shell so the are stable

4 0
3 years ago
Which of the following is a testable hypothesis?
BartSMP [9]
I think A would be the right answer because it is an educational guess that is able to be tested. C is not the right answer because it is not and educational guess, its a question.
5 0
3 years ago
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