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san4es73 [151]
3 years ago
13

You watch a distant lady driving nails into her front porch at a regular rate of 2 strokes per second. You hear the sound of the

blows exactly synchronized with the blows you see. And then you hear one more blow after you see her stop hammering. How far away is she? The speed of sound is 340 m/s.
Physics
1 answer:
Harlamova29_29 [7]3 years ago
3 0

Since the lady is capable of delivering 2 strokes in 1 second, we know that it takes 0.5 seconds for one stroke of the hammer.

It is given that one more blow is heard even after she is seen as stopping hammering. This means that the sound from the last blow reached us a little later: 0.5 seconds after the last blow.

So, we know that time taken for the sound from the last blow to reach us t = 0.5 s

Speed of Sound is given as V = 340 m/s

Distance of the lady from us D = ?

Using the equation D = V.t, we get D = (340)(0.5) = 170 m

Thus, we can understand that the lady is 170 meters away from us.

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ANEK [815]

Answer:\dfrac{\pi}{2} ms^{-1}

Explanation:

Let T be the time required to make one revolution.

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As we know,the distance travelled in one revolution is the circumference of the circle.

So,d=2\pi r

Given,d=0.5m\\T=2sec

d=2\times \pi \times 0.5=\pi m

Speed of an object moving is circular path is define as the ratio of distance travelled in one revolution to the time taken by the object to complete one revolution.

Let s be the speed of the ball.

s=\frac{d}{T}=\frac{\pi }{2}ms^{-1}

So,the speed of the ball is \frac{\pi }{2}ms^{-1}

5 0
3 years ago
The period (T) of an oscillating wave is 1/5s. What happens to the frequency (f) of the wave if T increases to 1/2s
Anastasy [175]
Frequency = 1/T
as the 5 is reduced, frequency is increase.
as 1 whole wave travels through a point in a lesser time now
6 0
3 years ago
With each beat of your heart the aortic valve opens and closes. The valve opens and closes very rapidly, with a peak velocity as
Nonamiya [84]

Answer:

|Δf| = 37.3 kHz

Explanation:

given,

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v = C\dfrac{\pm \dlta f}{2 f_0}

\delta f = \pm 2 f_0 (\dfrac{V}{C})

\delta f = \pm 2\times 7 (\dfrac{4}{1500})

           =\pm 0.0373 MHz

           = 37.3 kHz

|Δf| = 37.3 kHz

hence, frequency shift between the opening and closing valve is 37.3 kHz

4 0
3 years ago
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kotykmax [81]

Answer:

0.29D

Explanation:

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F = G M m / r2

F = GM(6m) / (D-r)2

G Mm/r2 = GM(6m) / (D-r)2

1/r2 = 6 / (D-r)2

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See diagram in attached file

7 0
3 years ago
Olivia places her pet frog on a line to observe the frog’s motion. The line is divided into sections that measure 1 centimeter e
aalyn [17]

Answer:

Explanation:

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first displacement = + 18 cm

second displacement = - 6 cm

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4 0
3 years ago
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