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Vilka [71]
3 years ago
15

URGENT! PLEASE ANSWER!!

Physics
1 answer:
Marrrta [24]3 years ago
7 0

Answer:

C

Explanation:

The answer is obvious from the given figure

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You may make the following measurements of an object 42kg and 22m3. What would the objects density be?
ki77a [65]
Density=mass/volume
to find the density
mass=42kg
volume=22m3
so density=42/22
density=1.9Kgm3
8 0
4 years ago
Standing on the roof of a (42.0+A) m tall building, you throw a ball straight up with an initial speed of (14.5+B) m/s. If the b
RSB [31]
First, we must find the vertical distance traveled upwards by the ball due to the throw. For this, we will use the formula:

2as = v² - u²

Because the final velocity v is 0 in such cases

s = -u²/2a; because both u and a are downwards, the negative sign cancels

s = 14.5² / 2*9.81
s = 10.72 meters

Next, to find the time taken to reach the ground, we need the height above the ground. This is:
45 + 10.72 = 55.72 m

We will use the formula 
s = ut + 0.5at²

to find the time taken with the initial velocity u = 0.

55.72 = 0.5 * 9.81 * t²

t = 3.37 seconds
4 0
4 years ago
If it takes 200 joules of energy to lift a bucket of water 3 meters in 2 seconds, how much power would be required to do the sam
Harlamova29_29 [7]

200 joules of work energy are involved.  That's all we need to know to answer the question.  Once we know that 200 joules of work energy are involved, we don't care what was lifted, or how far, or how long it took, or how many people worked on it, or how much they were paid, or what was the distribution of their gender identities, or the ethnic diversity among the team. or what day each of them celebrates as their sabbath.  Any other information besides the 200 joules is only there to distract us, and see whether we're paying attention.

Power = (work or energy) / (time to do the work or move the energy)

Power = (200 joules) / (5 seconds)

<em>Power = 40 watts</em>

3 0
4 years ago
If you know this please help
Ainat [17]

Answer:

b.

Explanation:

It's b I sis thebksqjwnsx0qkqnsnd991isnd

3 0
3 years ago
Read 2 more answers
Let two objects of equal mass m collide. Object 1 has initial velocityv, directed to the right, and object 2 isinitially station
3241004551 [841]
<span>Our equation 1 would be
m*v=M*V1+m*V2
v=V1+V2
 v-V1=V2 

the equation 2 would look like this
 </span>V^2=V1^2+V2^2  
V^2-V1^2=V2^2
(V-V1)*(V+V1)=V2^2Dividing with the 1
V+V1=V2 
8 0
3 years ago
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