Answer:
= 1.75 × 10⁻⁴ m/s
Explanation:
Given:
Density of copper, ρ = 8.93 g/cm³
mass, M = 63.5 g/mol
Radius of wire = 0.625 mm
Current, I = 3A
Area of the wire, =
Now,
The current density, J is given as
= 2444619.925 A/mm²
now, the electron density,
where,
=Avogadro's Number
Now,
the drift velocity,
where,
e = charge on electron = 1.6 × 10⁻¹⁹ C
thus,
= 1.75 × 10⁻⁴ m/s
Answer:
Explanation:
Given
Initial speed
distance traveled before coming to rest
using equation of motion
where v=final velocity
u=initial velocity
a=acceleration
s=displacement
for
using same relation we get
divide 1 and 2 we get
So a distance if 213.32 ft is required to stop the vehicle with 80 mph speed
Answer:
Explanation:
Given
mass of ball m=10 kg
It is placed at a height of 150 m
It is dropped from the height and allowed to free fall for 40 m
Velocity acquired by the ball during this fall is given by
Insert u=0, a=g
Kinetic energy at this instant
Answer:
2000 kg m/s
Explanation:
The momentum of an object is a vector quantity whose magnitude is given by
where
m is the mass of the object
v is the velocity of the object
and its direction is the same as the velocity.
In this problem, we have:
- Spaceship 1 has
m = 200 kg (mass)
v = 0 m/s (zero velocity)
So its momentum is
- Spaceship 2 has
m = 200 kg (mass)
v = 10 m/s (velocity)
So its momentum is
Therefore, the combined momentum of the two spaceships is