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Kamila [148]
3 years ago
15

For a human zygote to become an embryo it must undergo

Physics
2 answers:
slava [35]3 years ago
8 0
Only mitotic divisions change the zygote to embryo. The other sentences are related to the way zygote is created
AleksAgata [21]3 years ago
8 0

Answer: D) mitotic división

A zygote is a diploid cell which forms after the fusion of the haploid male gamete (sperm) and female gamete (ovum) during fertilization. The human zygote goes through with the process of mitosis, in which each cell divides into two daughter cells.  The cell division continues for long and this gives rise to a multi-cellular embryo. These cells are called as totipotent cells because they have the ability to develop into specialized structure in a typically embryo.

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Which of these energy transformations is not part of how a nuclear power plant
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I think the second one
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A graph is provided below. The graph shows the speed of a car traveling
Elis [28]

Answer:

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Explanation:

5 0
3 years ago
A force of 2N will stretch a rubber band 0.02m. Assuming that Hooke's Law applies, answer the following: How far will a 1600N fo
denis-greek [22]
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7 0
3 years ago
If I connect an inductor (L) to a capacitor (C), I will get an LC oscillator circuit with some natural frequency omega. If I wer
mart [117]

The new natural frequency would be ω/2.

we know that,

f = \frac{1}{2 pi \sqrt{LC} } = ω.       -> equation 1

now, when capacitance is quadrupled,

f' = \frac{1}{2 pi \sqrt{L ( 4C )} }

f' = \frac{1}{2 pi (2)\sqrt{LC} }.           -> equation 2

substituting value of equation 1 in equation 2 , we get,

f' = \frac{w}{2}

Hence, the new natural frequency of the circuit is ω/2.

what do you mean by frequency ?

The resonant frequency for a particular circuit is the frequency at which this equality stands true. Where L is the inductance in henries and C is the capacitance in farads, this is the  LC circuit's resonant frequency.

Learn more about frequency here:-

brainly.com/question/12530980

#SPJ4

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