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2 years ago

15

For a human zygote to become an embryo it must undergo

2 answers:

slava [35]2 years ago

8 0

Only mitotic divisions change the zygote to embryo. The other sentences are related to the way zygote is created

AleksAgata [21]2 years ago

8 0

Answer: D) mitotic división

A zygote is a diploid cell which forms after the fusion of the haploid male gamete (sperm) and female gamete (ovum) during fertilization. The human zygote goes through with the process of mitosis, in which each cell divides into two daughter cells. The cell division continues for long and this gives rise to a multi-cellular embryo. These cells are called as totipotent cells because they have the ability to develop into specialized structure in a typically embryo.

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A scooter is accelerated from rest at the rate of 8m/s

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Which statement is supported by this scenario?

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2 years ago

Read 2 more answers

in a one dimensional collision, a 4kg object and 6 kg onject have initial velocity. calculate the magnitude of impulse

Greeley [361]

in a one dimensional collision, a 4kg object with 5ms^1 and 6 kg object with 2ms^1 have initial velocity, the magnitude of impulse is 12 , 18

given,

mass 1 = 4kg

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brainly.com/question/16980676

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8 0

10 months ago

A stretched string has a mass per unit length of 5.40 g/cm and a tension of 17.5 N. A sinusoidal wave on this string has an ampl

kondaur [170]

Answer:

Part a)

$y_m = 0.157 mm$

part b)

$k = 101.8 rad/m$

Part c)

$\omega = 579.3 rad/s$

Part d)

here since wave is moving in negative direction so the sign of $\omega$ must be positive

Explanation:

As we know that the speed of wave in string is given by

$v = \sqrt{\frac{T}{m/L}}$

so we have

$T = 17.5 N$

$m/L = 5.4 g/cm = 0.54 kg/m$

now we have

$v = \sqrt{\frac{17.5}{0.54}}$

$v = 5.69 m/s$

now we have

Part a)

$y_m$ = amplitude of wave

$y_m = 0.157 mm$

part b)

$k = \frac{\omega}{v}$

here we know that

$\omega = 2\pi f$

$\omega = 2\pi(92.2) = 579.3 rad/s$

so we have

$k = \frac{579.3}{5.69}$

$k = 101.8 rad/m$

Part c)

$\omega = 579.3 rad/s$

Part d)

here since wave is moving in negative direction so the sign of $\omega$ must be positive

4 0

3 years ago