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Aleks [24]
3 years ago
14

How do exited atoms give off light

Physics
1 answer:
mrs_skeptik [129]3 years ago
5 0
Light is produced by the change of state of energy of an electron. Within an atom, there are multiple electron "shells". 'Excited' atoms are those where the electrons are moving in between shells. The electrons move because they are given energy enough to move to a different shell; however, they are unstable and cannot remain in their new position. When moving back to its original shell, the electron loses energy - but energy can't be created nor destroyed so they release a photon. 
There's other ways light may be produced, but always it is produced as a result of transmission of energy (in some form). Also, light is usually produced in conjunction with other forms of energy such as sound or heat. 
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An airplane takes off from Dallas Texas to fly to new york city traveling ne for 2,760 km the Same plane returns that day to Dal
Kipish [7]
<h3>Answer</h3>

1104 km/hour

<h3>Explanation</h3>

Distance between Dallas Texas to New York = 2760 km

Time the plane took from Dallas to New York = 2 hours

Time the plane took from New York back to Dallas = 2.5 hours

Formula to use

<h3>distance = speed x time </h3>

Speed the plane took from Dallas to New York

2760 = 2 x speed

speed = 2760 / 2

          = 1380 km/hour

Speed the plane took from New York to Dallas (ROUND TRIP)

2760 = 2.5 x speed

speed = 2760 / 2.5

           = 1104 km/hour

3 0
3 years ago
Read 2 more answers
Tom has two pendulums with him. Pendulum 1 has a ball of mass 0.2 kg attached to it and has a length of 5 m. Pendulum 2 has a ba
mars1129 [50]

Given Information:

Pendulum 1 mass = m₁ = 0.2 kg

Pendulum 2 mass = m₂ = 0.6 kg

Pendulum 1 length = L₁ = 5 m

Pendulum 2 length = L₂ = 1 m

Required Information:

Affect of mass on the frequency of the pendulum = ?

Answer:

The mass of the ball will not affect the frequency of the pendulum.

Explanation:

The relation between period and frequency of pendulum is given by

f = 1/T

The period of pendulum is given by

T = 2π√(L/g)

Where g is the acceleration due to gravity and L is the length of the string

As you can see the period (and frequency too) of pendulum is independent of the mass of the pendulum. Therefore, the mass of the ball will not affect the frequency of the pendulum.

Bonus:

Pendulum 1:

T₁ = 2π√(L₁/g)

T₁ = 2π√(5/9.8)

T₁ = 4.49 s

f₁ = 1/T₁

f₁ = 1/4.49

f₁ = 0.22 Hz

Pendulum 2:

T₂ = 2π√(L₂/g)

T₂ = 2π√(1/9.8)

T₂ = 2.0 s

f₂ = 1/T₂

f₂ = 1/2.0

f₂ = 0.5 Hz

So we can conclude that the higher length of the string increases the period of the pendulum and decreases the frequency of the pendulum.

3 0
2 years ago
Read 2 more answers
Select all the correct answers.
Anastasy [175]
The ground exerts an equal force on the golf ball
8 0
2 years ago
What is kelvin scale?
Darina [25.2K]
<span>a scale of temperature with absolute zero as zero, and the triple point of water as exactly 273.16 degrees.</span>
4 0
3 years ago
Read 2 more answers
Pls help and thank u need asap!
aleksandr82 [10.1K]

Answer:

ill help if u help me?its 4am

5 0
2 years ago
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