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3 years ago

Find the solution set for x2 + 3x – 40 = 0.

1 answer:

8 0

I am going to assume that x2 = x squared
So: X^2 + 3x -40
= (X+8)(X-5)=0

X+8 = 0
X= - 8

The other solution is X -5 = 0
X = 5

Therefore the solution set is {-8, 5}

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Which equation represents the graph shown?<br> (Picture attached)

Maurinko [17]

Answer:

correct answer is option B

Step-by-step explanation:

as we know equation of line

y = m x + c....................(1)

where c is the intercept

m is the slope

m = $\dfrac{y_2-y_1}{x_2-x_1}$

m = $\dfrac{35-0}{1-0}$

m = 35

putting value of m in equation (1)

we get

y = 35 x + c

from the graph we can clearly see that line is passing through (0,0) hence

0 = 35 (0)x + c

c = 0

hence the equation of line comes out to be

y = 35 x

correct answer is option B

8 0

3 years ago

PLS HELP NEED THIS IN LESS THA AN HOUR PLS NO LINKS

yanalaym [24]

Answer:

Volume=Length×Width×Height

Step-by-step explanation:

A rectangular prism is a 3D figure with 6 rectangular faces. To find the volume of a rectangular prism, multiply its 3 dimensions: length × width × height. The volume is expressed in cubic units.

EXAMPLE:

Lets say the HEIGHT is 2mm. Lets say the WIDTH is 1mm. Lets say the LENGTH is 10mm.

L×W×H

10×1×2=20mm

20 Cubic mm

Brainliest pls?

3 0

3 years ago

If line lis parallel to line m, find the value of x and y. (please help taking a test)

castortr0y [4]

Answer:

x=8 and y=21

Step-by-step explanation:

12x-28=7x+12 (the 2 angles are equivalent)

12x-7x=12+28

5x=40

x=8

9y-77 + 12x-28 =180 (the sum of those 2 angles is a flat angle (180°))

9y-77+12*8-28=180

9y=180+28+77-96

9y=189

y=21

3 0

3 years ago

find continued product of (x+y) (x-y) (<img src="https://tex.z-dn.net/?f=x%5E%7B2%7D" id="TexFormula1" title="x^{2}" alt="x^{2}"

leonid [27]

Answer:

$\large\boxed{(x+y)(x-y)(x^2+y^2)(x^4+y^4)=x^8-y^8}$

Step-by-step explanation:

$(x+y)(x-y)(x^2+y^2)(x^4+y^4)\\\\\text{use}\ (a-b)(a+b)=a^2-b^2\qquad(*)\\\\=\underbrace{(x+y)(x-y)}_{(*)}(x^2+y^2)(x^4+y^4)\\\\=\underbrace{(x^2-y^2)(x^2+y^2)}_{(*)}(x^4+y^4)\\\\=\left((x^2)^2-(y^2)^2\right)(x^4+y^4)\qquad\text{use}\ (a^n)^m=a^{nm}\\\\=\underbrace{(x^4-y^4)(x^4+y^4)}_{(*)}\\\\=\left(x^4\right)^2-\left(y^4\right)^2=x^8-y^8$

7 0

3 years ago

If y varies directly as x, and y is 20 when x is 4, what is the constant of variation for this relation?

VARVARA [1.3K]

Answer:

k = 5

Step-by-step explanation:

Given y varies directly as x then the equation relating them is

y = kx ← k is the constant of variation

To find k use the condition y = 20 when x = 4, then

20 = 4k ( divide both sides by 4 )

5 = k

3 0

3 years ago

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