Parallel lines have the same slope, but different y-intercepts
The slope of both lines is -2/3
To find the equation that passes through (7, 3) we can use the point-slope formula: y - y1 = m (x - x1)
y - (3) = (-2/3) (x - (7))
y - 3 = -2/3x + 4 and 2/3
y = -2/3x + 7 and 2/3
or
y = -2/3x + 7.67
:)))
Answer: wheres the picture
Step-by-step explanation:
Answer is Provided in the image attached.
Please, use " ^ " to denote exponentiation: p(t) = t^2 + 5t + 6.
To find the critical points, differentiate p(t) with respect to t, set the result = to 0, and then solve the resulting equation for t:
p '(t) = 2t + 5 = 0
Solving for t: 2t = -5, and so t = -5/2. (-5/2, p(-5/2)) is the critical point. That evaluates to (-5/2, -0.25). This happens to be the vertex of a parabola that opens up.
