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In-s [12.5K]
1 year ago
15

Match the average rates of change of f(x) to the corresponding intervals.

Mathematics
1 answer:
spin [16.1K]1 year ago
6 0

The average rates of change of f(x) and their corresponding intervals are given as:

Interval          Rate of Change

[-5, -1]                 -8

[-4, -1]                 -7

[-3, 1]                  -4

[-2, 1]                  -3.

<h3>What is the explanation for the above?
</h3>

Step 1 - See Table Attached

Step 2 - State the formula for rate of change

The formula for rate of change is given as:
= [change in f(x)] / [change in x]

a) For interval [5, -1] ⇒

Rate of Change - [ f(1) - f(-5) ] / [-1 - (-5)]  

= [-1 - 35] / [-1+5]

= -36 / 4

= - 8

b) For interval [-4, -1] ⇒

rate of change = [ f(-1) - f(-4) ] / [ -1 - (-4) ]

= [3 - 24] / [-1 + 4]

= -21/3

= - 7

c) interval [-3,1] ⇒

rate of change = [ f(1) - f(-3) ] / [ 1 - (-3) ]

= [-1 - 15] / [1 + 3]

= -16/4

= - 4

d) interval [-2,1] ⇒

rate of change = [f (1) - f(-2)] / [1 - (-2)]

= [ -1 - 8] / [1 + 2]

= -9/3

= -3

Learn more about rate of change at:
brainly.com/question/25184007
#SPJ1

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What is <br><img src="https://tex.z-dn.net/?f=8.4%20-%204.2" id="TexFormula1" title="8.4 - 4.2" alt="8.4 - 4.2" align="absmiddle
STALIN [3.7K]

Answer:

4.2

Step-by-step explanation:

\mathrm{Write\:the\:numbers\:one\:under\:the\:other,\:line\:up\:the\:decimal\:points.}

\mathrm{Add\:trailing\:zeroes\:so\:the\:numbers\:have\:the\:same\:length.}

\begin{matrix}\space\space&8&.&4\\ -&4&.&2\end{matrix}

\mathrm{Subtract\:each\:column\:of\:digits,\:starting\:from\:the\:right\:and\:working\:left}

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\frac{\begin{matrix}\space\space&8&.&\textbf{4}\\ -&4&.&\textbf{2}\end{matrix}}{\begin{matrix}\space\space&\space\space&\space\space&\textbf{2}\end{matrix}}

\mathrm{Place\:the\:decimal\:point\:in\:the\:answer\:directly\:below\:the\:decimal\:points\:in\:the\:terms}

\frac{\begin{matrix}\space\space&8&\textbf{.}&4\\ -&4&\textbf{.}&2\end{matrix}}{\begin{matrix}\space\space&\space\space&\textbf{.}&2\end{matrix}}

\mathrm{In\:the\:bolded\:column,\:subtract\:the\:second\:digit\:from\:the\:first}:\quad \:8-4=4

\frac{\begin{matrix}\space\space&\textbf{8}&.&4\\ -&\textbf{4}&.&2\end{matrix}}{\begin{matrix}\space\space&\textbf{4}&.&2\end{matrix}}

=4.2

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Answer:

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Step-by-step explanation:

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