Be more specific. Like what is it asking you to do ? I'm trying to help. :)
<u><em>#10.</em></u> In order to find a ratio, all we need to do is set up a simple equation and then cross-multiply!
I'll show you !
In this case, we'll take the <u>already established ration </u><u>(14 : 8 )</u> and find the equivalent ratio where <u>7 is in place of 14 </u><u>(7: x) </u>
x will be the other table value we are looking for!
Now let's set up the equation and cross-multiply!

<u>cross multiply 14 and x, then 8 and 7 </u>
We get: 14x = 56
solve to find x!
x = 56/14
x = 4 blankets
Now let's use the ratio 7: 4 to find what goes with 16 in the table!

4x = 112
x = 112/4
x = 28 towels
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<u><em>#11. : </em></u>Using the same method, I'll fill in the values of the table on #11
16 forks, 10 spoons
8 forks, 5 spoons,
48 forks, 30 spoons
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<u><em>#12. </em></u>If the neighbor pays you $17 for every 2 hours of work, we need to find <u><em>how many times 2 hours goes in 8 hours of work</em></u>
We do this by dividing
8/2 = 4 times
2 hours of work goes into 8, 4 times!
Now we multiply 4 by $17 to find how much your neighbor owes you!
$17 × 4 = $68
Your neighbor owes you $68 !!!
Answer:
C. {2, 4, 5}
Step-by-step explanation:
We are given a function mapping.
The first diagram represents the domain and the second one represents the range.
The set of all range = {2, 4, 5}
Answer: C. {2, 4, 5}
Hope you will understand the concept.
Thank you.
Answer:
y=-0.215x^2+35
Step by Step:
Let,
,
,
, 
We know that, the general equation of the parabola.


Substitute the value of
in equation
and find the value of 







Hence, the equation of the parabola is:

Answer:
2l + 2w = 96 ..... eqn1
lw = 504 ...... eqn2
Step-by-step explanation:
To model this case where we have two unknowns l and w, we need two equations.
Firstly, the perimeter of a rectangle is given by
2l + 2w = p
Where l,w and p are length, width and perimeter of the rectangle respectively.
Hence,
2l + 2w = 96 ... eqn1
Secondly, the area of a rectangle is given by
Length × width = Area
Hence,
l × w = 504
lw = 504 ... eqn2
With these two equations the solutions to the length and width of the rectangular pool can be derived.