Answer:
Step-by-step explanation:
Hello : let A(2,3) B(4,6)
the slope is : (YB - YA)/(XB -XA)
(6-3)/(4-2) = 3/2
an equation is : y=ax+b a is a slope
y = (3/2)x +b
the line through point (2,3) : 3 = (3/2)(2)+b
b = 0
the equation is : y =(3/2)x
H = 5 + ut - 16t^2
When the balls falls back to the ground, h = 0
0 = 5 + 3.2u - 16(3.2)^2
0 = 5 + 3.2u - 163.84
0 = 3.2u - 158.84
3.2u = 158.84
u = 158.84/3.2 = 49.6 ft/s
Required equation is
h = 5 + 49.6t - 16t^2
Answer:
(2 x 1) + (6 x 1/1,000)
2 + (6)(0.001)
2 + 0.006
2.006
Step-by-step explanation:
Answer:
x = 2 , 3/2
Step-by-step explanation:
