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PtichkaEL [24]
2 years ago
14

Question 12 A wave has a wavelength of 7.96 m and travels at 30.67 m/s. What is the frequency of the wave?​

Physics
1 answer:
KonstantinChe [14]2 years ago
7 0

Answer:

0.2597hertz

Explanation:

first of all we have to calculate time.

time is given by speed/distance

hence=30.67/7.96

=3.85s

frequency is given by 1/time

=1/3.85

=0.2597hertz

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What can cause you to observe that sone objects fall faster than others?
bekas [8.4K]

Galileo discovered that objects that are more dense, or have more mass, fall at a faster rate than less dense objects, due to this air resistance. A feather and brick dropped together. Air resistance causes the feather to fall more slowly.

3 0
3 years ago
An astronaut weighs 8.00 × 102 newtons on the sur- face of Earth. What is the weight of the astronaut 6.37 × 106 meters above th
kolbaska11 [484]

Answer:

mg=200.4 N.

Explanation:

This problem can be solved using Newton's law of universal gravitation: F=G\frac{m_{1}m_{2}}{r^{2}},

where F is the gravitational force between two masses m_{1} and m_{2}, r is the distance between the masses (their center of mass), and G=6.674*10^{-11}(m^{3}kg^{-1}s^{-2}) is the gravitational constant.

We know the weight of the astronout on the surface, with this we can find his mass. Letting w_{s} be the weight on the surface:

w_{s}=mg,

mg=8*10^{2},

m=(8*10^{2})/g,

since we now that g=9.8m/s^{2} we get that the mass is

m=81.6kg.

Now we can use Newton's law of universal gravitation

F=G\frac{Mm}{r^{2}},  

where m is the mass of the astronaut and M is the mass of the earth. From Newton's second law we know that

F=ma,

in this case the acceleration is the gravity so

F=mg, (<u>becarefull, gravity at this point is no longer</u> 9.8m/s^{2} <u>because we are not in the surface anymore</u>)

and this get us to

mg=G\frac{Mm}{r^{2}}, where mg is his new weight.

We need to remember that the mass of the earth is M=5.972*10^{24}kg and its radius is 6.37*10^{6}m.

The total distance between the astronaut and the earth is

r=(6.37*10^{6}+6.37*10^{6})=2(6.37*10^{6})=12.74*10^{6} meters.

Now we can compute his weigh:

mg=G\frac{Mm}{r^{2}},

mg=(6.674*10^{-11})\frac{(5.972*10^{24})(81.6)}{(12.74*10^{6})^{2}},

mg=200.4 N.

5 0
3 years ago
Derive an algebraic equation for the vertical force that the bench exerts on the book at the lowest point of the circular path i
fiasKO [112]

Answer:

The algebraic equation is:

F_{v} =\frac{m_{b}v_{b}^{2}   }{R} -m_{b} g

Explanation:

Given information:

mb = book's mass

vb = tangential speed

R = radius of the path

Question: Derive an algebraic equation for the vertical force, Fv = ?

To derive the equation, we need to draw a force diagram for this case, please, see the attached diagram. As you can see, there are three types of forces acting on the system. Two up and one of the weight acting down. Therefore, the algebraic equation is as follows:

F_{v} =\frac{m_{b}v_{b}^{2}   }{R} -m_{b} g

The variables were defined above and g is the gravity.

4 0
4 years ago
You must make an aqueous solution that will be a good conductor of electricity. You can pick two substances to add to the water.
mr_godi [17]

Answer: The answer is hydrochloric acid

And Salt

Explanation:

4 0
3 years ago
How??? help!!! please!!
pentagon [3]

Answer:

a. slope=rise/run

rise=2

run=10

slope=2/10

slope=1/5

used point (0,0) and (10,2)

slope(m)=1/5

b. area= 0.5bh

0.5×50s×10m/s

a=25s×10m/s

a=250m

c.the area represents the total distance traveled after 50s by the toy

the slope represents the acceleration of the toy

the unit of slope is m/s²

slope=rise/run

slope(m)=(2m/s)÷10s

m=(2/10)m/s/s

m=(1/5)m/s²

.=0.2m/s²

please mark brainliest

6 0
3 years ago
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