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PtichkaEL [24]
2 years ago
14

Question 12 A wave has a wavelength of 7.96 m and travels at 30.67 m/s. What is the frequency of the wave?​

Physics
1 answer:
KonstantinChe [14]2 years ago
7 0

Answer:

0.2597hertz

Explanation:

first of all we have to calculate time.

time is given by speed/distance

hence=30.67/7.96

=3.85s

frequency is given by 1/time

=1/3.85

=0.2597hertz

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Definition electromagnetic spectrum
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The spectrum in which the frequency and wavelength of electromagnetic radiation fall into in relation to each other.
3 0
3 years ago
The boiling point of water at sea level is 100 °c. at higher altitudes, the boiling point of water will be
Scilla [17]
   <span> The boiling point of water at sea level is 100 °C. At higher altitudes, the boiling point of water will be.....
a) higher, because the altitude is greater.
b) lower, because temperatures are lower.
c) the same, because water always boils at 100 °C.
d) higher, because there are fewer water molecules in the air.
==> e) lower, because the atmospheric pressure is lower.
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Water boils at a lower temperature on top of a mountain because there is less air pressure on the molecules.
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I hope this is helpful. </span>
8 0
3 years ago
A submarine deep underwater releases a bubble of air. The total pressure at this depth is P. The bubble has diameter, D, and abs
Sunny_sXe [5.5K]

Answer:

P V = n R T      ideal gas equation

P2 V2 / P1 V1 = T2 / T1    

V2 / V1 = T2 / T1 * P1 / P2 = T2 P1 / (T1 P2)

V2 / V1 = (1.17 T1) / T1 * (P1 / .22 P1)      assuming absolute temp as 1.17 P1

V2 / V1 = 1.17 / .22 = 5.32

V = 4/3 pi R^3 = 4/3 pi (D/2)^3 = 4/3 pi D^3 / 8 = pi D^3 / 6

V2 / V1 = D2^3 / D1^3

D2 = (V2 / V1 * D1^3)^1/3

D2 = 5.32^1/3 * D = 1.75 D      (D1 = D)

7 0
3 years ago
You throw a ball with a mass of 0.50 kg against a brick wall. It hits the wall moving horizontally to the left at 20 m/s and reb
Orlov [11]

Answer:

The value of impulse of the net force on the ball during its collision with wall is  I = 15\ kg \frac{m}{s}

The value of average horizontal force that the wall exerts on the ball during the impact is F = 15000 N

Explanation:

Mass of the ball = 0.5 kg

Horizontal velocity V_{x} = 20 \frac{m}{s}

Velocity after collision V_{-x} = - 10 \frac{m}{s}

(A). Impulse of the net force on the ball during its collision with wall is

I =  m (V_{x} - V_{-x})

I = 0.5 × (20 + 10)

I = 15\ kg \frac{m}{s}

This is the value of impulse of the net force on the ball during its collision with wall.

(B). The magnitude of average horizontal force

F = \frac{I}{T}

Where F = Force

I = impulse & t = time interval = 0.001 sec

F = \frac{15}{0.001}

F = 15000 N

This is the value of average horizontal force that the wall exerts on the ball during the impact.

8 0
3 years ago
If a 0.15 kg ball falls and has a KE of 20 J just before striking the ground, from what height did it fall. A. 1.36m B. 3m C. 13
RUDIKE [14]
According to the conservation of mechanical energy, the kinetic energy just before the ball strikes the ground is equal to the potential energy just before it fell. 

Therefore, we can say KE = PE
We know that PE = m·g·h

Which means KE = m·g·h

We can solve for h:

h = KE / m·g
   = 20 / (0.15 · 9.8) 
   = 13.6m

The correct answer is: the ball has fallen from a height of 13.6m.

5 0
3 years ago
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