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3 years ago

No, this question isn't abt language arts, mathematics. Im asking u this How are u doing? c:

Physics

1 answer:

nekit [7.7K]3 years ago

3 0

Answer:

horrible, but how about you?

Explanation:

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Which explains the downward force produced when air flows over the winglike spoiler on a race car?

professor190 [17]

Newton's principle
newton's 2nd law of motion where F=ma

3 0

3 years ago

* CRIMINOLOGY*

Setler [38]

I think the answer is B.

Hope this helps.

5 0

4 years ago

Read 2 more answers

How does an atom of rubidium-85 become a rubidium ion with a +1 charge?

Nastasia [14]

Answer:

C. The atom loses 1 electron to have a total of 36.

Explanation:

Cations have a positive charge. Cations lose electrons.

The number of electrons in a Rubidium atom is 37. If the atom loses 1 electron, then it has 36 left.

6 0

4 years ago

The Magnetic Dipole Moment of a Coil Problem A rectangular coil of dimensions 5.40 cm ✕ 8.50 cm consists of 25 turns of wire and

butalik [34]

Answer:

$\mu = 0.0023 \ A\cdot m^2$

$\tau = 0.00080 \ N \cdot m$

Explanation:

From the question we are told that

The dimensions of the rectangular coil is 5.40 cm ✕ 8.50 cm = 0.054 m X 0.085 m

The number of turns is $N = 25 \ turns$

The current it is carrying is $I = 20 \ mA = 0.02 \ A$

The magnetic field is $B = 0.350 \ T$

Generally the magnitude of the magnetic dipole moment is mathematically represented as

$\mu = N * I * A$

Here A is the area which is mathematically represented as

$A = 0.054 * 0.085$

=> $A = 0.00459 \ m^2$

$\mu = 25 * 0.02 * 0.00459$

=> $\mu = 0.0023 \ A\cdot m^2$

Generally the magnitude of the torque acting on the loop is mathematically represented as

$\tau = \mu * B$

=> $\tau = 0.0023 * 0.350$

=> $\tau = 0.00080 \ N \cdot m$

8 0

3 years ago

How much more mass does 12Mg have than 12g

Masja [62]

Explanation:

Given that,

First mass, $m_1=12\ Mg$

Other mass, $m_2=12\ g$

We know that,

1 Megagram (Mg) = 10⁶ grams (g)

So, $1\ g=10^{-6}\ Mg$

Using unitary method,

$m_2=12\ g=12\times 10^{-6}\ Mg$

So, $m_1-m_2=12\ Mg-12\times 10^{-6}\ Mg$

$m_1-m_2=10^{-6}$

So, the mass of 12 Mg is $10^{-6}$ more than 12 grams. Hence, this is the required solution.

4 0

3 years ago