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andrey2020 [161]
3 years ago
7

What factors can limit the growth of the human population?

Biology
1 answer:
tresset_1 [31]3 years ago
5 0
We would over populate the eart leading to no water or no food, we would eventually go into a fallout and have nuculer war and then everything is gonna go to sh and we are going to have to repopulate 
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Nezavi [6.7K]
The most energy is always at the bottom of the food chain so C. <span>#TeamAlvaxic</span>
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3 years ago
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In the Calvin cycle the conversion of energy poor carbon dioxide into energy rich glucose
rodikova [14]

Answer:

D)NADPH is made

A)ATP is used

Explanation:

Sorry to ask the two questions, I asked why the two options are in the process:Reduction. In the second stage, ATP and NADPH are used to convert the 3-PGA molecules into three-carbon sugar molecules, glyceraldehyde-3-phosphate ( G3P ). At this stage, it gets its name because NADPH donates, or reduces , electrons to a three-carbon intermediate to form G3P.[Ocultar detalhes]

The reduction stage of the Calvin cycle, which needs ATP and NADPH, converts 3-PGA (produced in the fixation stage) into a three-carbon sugar. This process takes place in two main stages:

Simplified diagram of the reduction step of the Calvin cycle showing the carbon atoms, but not the complete molecular structures. A 3-PGA molecule first receives a second phosphate group from ATP (generating ADP). Then, the doubly phosphorylated molecule receives electrons from NADPH and is reduced to form glyceraldehyde-3-phosphate. This reaction generates NADP + and also releases an inorganic phosphate.

Simplified diagram of the reduction step of the Calvin cycle showing the carbon atoms, but not the complete molecular structures. A 3-PGA molecule first receives a second phosphate group from ATP (generating ADP). Then, the doubly phosphorylated molecule receives electrons from NADPH and is reduced to form glyceraldehyde-3-phosphate. This reaction generates NADP + and also releases an inorganic phosphate.

First, each 3-PGA molecule receives a phosphate group from ATP, becoming a doubly phosphorylated molecule called 1,3-bisphosphoglyceride (and leaving an ADP as a by-product).

Second, 1,3-bisphosphoglycerate molecules are reduced (gain electrons). Each molecule receives two electrons from NADPH and loses one of its phosphate groups, becoming a three-carbon sugar called glyceraldehyde-3-phosphate (G3P) . This step produces NADP^+

+

start superscript, plus, end superscript and phosphate (\text P_iP

i

start text, P, end text, start subscript, i, end subscript) as by-products.

The chemical structures and real reactions are:

Reactions of the Calvin cycle reduction step, showing the molecular structures of the molecules involved.

Reactions of the Calvin cycle reduction step, showing the molecular structures of the molecules involved.

The ATP and NADPH used in these steps are products of the photo-dependent reactions (first stage of photosynthesis). That is, the chemical energy of ATP and the reducing potential of NADPH, both produced with the use of light energy, keep the Calvin cycle running. Conversely, the Calvin cycle regenerates ADP and NADP^+

+

start superscript, plus, end superscript, providing the necessary substrates for photo-dependent reactions.

7 0
2 years ago
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Does cellular respiration follow the law of conservation of energy?
k0ka [10]

Yes. Every chemical reaction obeys the law of conservation of mass.

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8 0
3 years ago
What step in photosynthesis may occur during day and night? A.Light independant reactions B.Light dependant reactions c. Photoly
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Answer:

a is the answer

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6 0
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Imagine you do a test cross between a purple-flowered pea plant having serrated leaves (a dominant trait) and a white-flowered p
Rom4ik [11]

Answer:

genes for flower color and edge shape are linked. They do not assort independently.

Explanation:

<u>Available data:</u>

  • test cross between a purple-flowered pea plant having serrated leaves and a white-flowered pea plant having smooth edges.
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  • smooth edges → recessive trait
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There are two genes involved in the cross. The expected ratios are 1:1:1:1 because we assume genes assort independently. However, we see a different phenotypic distribution. When phenotypic ratios differ from the expected ones, it means that genes are linked.

To know if two genes are linked in the same chromosome, we must observe the progeny distribution. If individuals, whose genes assort independently, are test crossed, they produce a progeny with equal phenotypic frequencies 1:1:1:1. But if instead of this distribution, we observe a different one, that is that phenotypes appear in different proportions, we can assume that genes are linked in the double heterozygote parent

 

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3 years ago
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