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avanturin [10]
3 years ago
15

What is the general formula for alkynes​

Chemistry
2 answers:
Sphinxa [80]3 years ago
8 0

Answer: Cn H 2n- n

Explanation: Alkynes are organic compounds that contains a hydrocarbon a Hydrogen and Carbon composition. For alkynes, an indicator is the presence of a single triple bond in its structure.

ss7ja [257]3 years ago
7 0

Answer:CnH2n-2

Explanation:

The general formula for alkyne is

CnH2n-2

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Alja [10]

Answer:

I have it.

Explanation:

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3 years ago
How do you convert moles of a compound to mass?​
laiz [17]

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Divide the mass of the compound in grams by the molar mass you just calculated. The answer is the number of moles of that mass of compound

Explanation:

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- 5. Describe the general trend in atomic radil across a row of the periodic table.​
sattari [20]

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Across a row, atomic radii decreases.

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It decreases because nuclear charge increases across a row, electrons are added to the same shell and shielding remains constant. Therefore the outer electrons are more attracted to the nucleus making the atom smaller.

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3 years ago
For each equation , write all possible mole ratios . A. 2HgO(s)&gt;2Hg(l)+O2(g) B. 4NH3(g)+6NO(g)&gt;5N2(g)+6H2O(l)
Dafna11 [192]

A) For balanced chemical equation: 2HgO(s) → 2Hg(l) + O₂(g).

1) Mole ratio 1: n(HgO) : n(Hg) = 2 : 2 (1 : 1).

2) Mole ratio 2: n(HgO) : n(O₂) = 2 : 1.

3) Mole ratio 3: n(Hg) : n(O₂) = 2 : 1.

B) Balanced chemical equation: 4NH₃(g) + 6NO(g) → 5N₂(g) + 6H₂O(l).

1) Mole ratio 1: n(NH₃) : n(NO) = 4 : 6 (2 : 3).

2) Mole ratio 2: n(NH₃) : n(N₂) = 4 : 5.

3) Mole ratio 3: n(NH₃) : n(H₂O) = 4 : 6 (2 : 3).

4) Mole ratio 4: n(NO) : n(N₂) = 6 : 5.

5) Mole ratio 5: n(NO) : n(H₂O) = 6 : 6 (1 :1).

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3 0
4 years ago
Read 2 more answers
What are the units of k in the following rate law?
Ludmilka [50]

Answer:

B. \frac{1}{M^{2} s }

Explanation:

The unit for rate is M/s while the unit for each molecule should be M. You can find the unit for k by putting the units for rate and the molecules into the equation

rate= k{X][Y]

M/s= k * M^{2} * M^{1}

k= (M/s) / (M^{3})

k= \frac{1}{M^{2} s }

You can also use this predetermined formula to solve this problem faster: k= \frac{M^{1-n} }{s }

Where n is the number of molecule. There are 3 molecule(2X and 1Y) so n=3, so

k= \frac{M^{1-n} }{s }

k= \frac{M^{1-3} }{s }= \frac{m^{-2}}{s}= \frac{1}{M^{2} s }

8 0
4 years ago
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