2 years ago

What are the correct order of steps for expanding and simplifying 8(x+3)+4x

Mathematics

1 answer:

aalyn [17]2 years ago

6 0

8(x+3)+4x

8x + 24 + 4x

12x = 24

12x/12 = 24/12

x= 2

You might be interested in

On a coordinate plane, polygon GHIJ translates 8 units to the left to form polygon G 'H 'I 'J '. Which of the following equation

Ad libitum [116K]

G'G= 8 units ! B is the answer

8 0

3 years ago

Read 2 more answers

Please help with solving

Makovka662 [10]

N.O = 4
N is midpoint of M.0
Meaning M.N also has to be 4
4+4= 8
N.P = 6
0.P = 2
8+ 2 = 10

4 0

2 years ago

Evaluate the formula v=bh/3 for b = 36 in.2 and h = 11 in.

Over [174]

V=36times 11/3
v=132

4 0

3 years ago

Read 2 more answers

2x-8=4(x+1). Solve for X please!

julsineya [31]

Answer:

-6 = x

Step-by-step explanation:

2x-8=4(x+1)

Distribute

2x -8 = 4x+4

Subtract 2x

2x-8-2x = 4x-2x+4

-8 = 2x+4

Subtract 4

-8-4 = 2x+4-4

-12 = 2x

Divide by 2

-12/2 = 2x/2

-6 = x

6 0

2 years ago

Read 2 more answers

How to find the square root of complex numbers?? Find the square root of (6+8i) ??

ivann1987 [24]

Answer:

$2 \sqrt{2} + i \sqrt{2}$

Step-by-step explanation:

The square of a complex number is a complex number. Here, we have:

${(a + bi)}^{2} = 6 + 8i$

${a}^{2} + 2abi - {b}^{2} = 6 + 8i$

We then have this system of equations:

${a}^{2} - {b}^{2} = 6$

$2ab = 8$

Solving this system:

$ab = 4$

$b = \frac{4}{a}$

${a}^{2} - {( \frac{4}{a}) }^{2} = 6$

${a}^{2} - \frac{16}{ {a}^{2} } = 6$

${a}^{4} - 16 = 6{a}^{2}$

${a}^{4} - 6 {a}^{2} - 16 = 0$

$( {a}^{2} - 8)( {a}^{2} + 2) = 0$

${a}^{2} = 8$

$a = 2 \sqrt{2}$

$b = \frac{4}{2 \sqrt{2} } = \sqrt{2}$

6 0

2 years ago

Read 2 more answers