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Brrunno [24]
3 years ago
6

Help plzzzz this is hard

Mathematics
2 answers:
Brilliant_brown [7]3 years ago
5 0
I’m pretty sure it’s D.
anzhelika [568]3 years ago
3 0
Yes I think it’s D as well
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KonstantinChe [14]
<span>. 6 times a number is 6x, so quotient of 6x and 16 is the same as saying 6x16
</span>So your answer  is:=<span>96<span>x</span></span>
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What is x, the length of the diagonal, to the nearest whole number
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brainly being slow today so i did my work on this attachment

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3 years ago
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A machine that produces a major part for an airplane engine is monitored closely. In the past, 10% of the parts produced would b
nata0808 [166]

Answer:

With a .95 probability, the sample size that needs to be taken if the desired margin of error is .04 or less is of at least 216.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

For this problem, we have that:

p = 0.1

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

With a .95 probability, the sample size that needs to be taken if the desired margin of error is .04 or less is

We need a sample size of at least n, in which n is found M = 0.04.

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.04 = 1.96\sqrt{\frac{0.1*0.9}{n}}

0.04\sqrt{n} = 0.588

\sqrt{n} = \frac{0.588}{0.04}

\sqrt{n} = 14.7

(\sqrt{n})^{2} = (14.7)^{2}

n = 216

With a .95 probability, the sample size that needs to be taken if the desired margin of error is .04 or less is of at least 216.

7 0
4 years ago
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alisha [4.7K]

Answer:

3/5

Step-by-step explanation:

7/15 + 2/15 = 9/15

both 9 nad 15 are divisible by 3

9/15 = 3/5

6 0
3 years ago
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Answer:

Step-by-step explanation:

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