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Vanyuwa [196]
2 years ago
13

Jelly beans cost $2.00 for 4 packages. There were 25 students. How much money will be needed so that each

Mathematics
2 answers:
il63 [147K]2 years ago
6 0

Answer:

14$

Step-by-step explanation:

2 Packages Will Be Left Over

Sergeu [11.5K]2 years ago
3 0

Answer:

$14 and 3 bags

Step-by-step explanation:

25 divided by 4 = 7

7 muliplied by 4 = 28 and you need 25 so there will be 3 bags left over

$2 multiplied by 7 = $14 so it will cost $14

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Plz help
german
I think c. 10100÷ (12 x 4)
7 0
3 years ago
A researcher wants to see if a kelp extract helps prevent frost damage on tomato plants. One hundred tomato plants in individual
atroni [7]

Complete question is;

A researcher wants to see if a kelp extract helps prevent frost damage on tomato plants. One hundred tomato plants in individual containers are randomly assigned to two different groups. Plants in both groups are treated identically, except that the plants in group 1 are sprayed weekly with a kelp extract, while the plants in group 2 are not. After the first frost, 12 of the 50 plants in group 1 exhibited damage and 18 of the 50 plants in group 2 showed damage. Let p1 be the actual proportion of all tomato plants of this variety that would experience damage under the kelp treatment, and let p2 be the actual proportion of all tomato plants of this variety that would experience damage under the no-kelp treatment. Is there evidence of a decrease in the proportion of

tomatoes suffering frost damage for tomatoes sprayed with kelp extract? To determine

this, yo u test the hypotheses H0: p1 = p2, Ha: p1 < p2. The p - value of your test is

A) greater than 0.10.

B) between 0.05 and 0.10.

C) between 0.01 and 0.05.

D)between 0.001 and 0.01.

E) below 0.001.

Answer:

B) between 0.05 and 0.10.

Step-by-step explanation:

We are given;

Number of plants in group that exhibited damage = 12

Number of group 1 plants; n₁ = 50

Number of plants in group 2 that exhibited damage = 18

Number of group 2 plants; n₂ = 50

Proportion of plants in group 1 that exhibited damage; p₁^ = 12/50 = 0.24

Proportion of plants in group 2 that exhibited damage; p₂^ = 18/50 = 0.36

Pooled proportion; p¯ = (12 + 18)/(50 + 50) = 0.3

q¯ = 1 - p¯

q¯ = 1 - 0.3 = 0.7

Z-score will be;

z = ((p₁^ - p₂^) - 0)/√((p¯•q¯)×((1/n₁) + (1/n₂))

Plugging in the relevant values;

z = (0.24 - 0.36)/√((0.3 × 0.7) × ((1/50) + (1/50))

z = -0.12/0.092

z = -1.3

From z-distribution table attached, we have;

p-value = 0.0968

Correct answer is option B.

8 0
2 years ago
What is the prime factorization of 35? 1 • 35 12 • 5 • 7 1 • 5 • 7 5 • 7
Nonamiya [84]

Answer:

  5·7

Step-by-step explanation:

From your knowledge of multiplication tables, you know that ...

  5×7 = 35

Both 5 and 7 are prime numbers, so that is the prime factorization.

4 0
3 years ago
PLZ HElP!!! Simplify 10 – 3x – 13 + 5x 3 – 3x 1 2x – 3 3 – 2x
777dan777 [17]

the answer to the first part is 2x-3

4 0
3 years ago
A data set consists of the following data points:
aleksley [76]
<span>(3,5),
(5,8),
(6,13)
------
(14,26)/3
 
then use the point slope form of a line to find equation of line

</span>y-y_1=m(x-x_1)&#10;\\y -  \frac{26}{3}  = 2.5(x- \frac{14}{3})&#10;\\y -  \frac{26}{3}  =  \frac{5}{2} (x- \frac{14}{3})&#10;\\y -  \frac{26}{3}  =  \frac{5}{2} x-  \frac{5}{2}\times\frac{14}{3}&#10;\\y -  \frac{26}{3}  =  \frac{5}{2} x-  \frac{35}{3}&#10;\\6y-52=15x-70&#10;\\15x-6y-18=0
<span>
Find y-intercept for x = 0.

</span>15x-6y-18=0&#10;\\15\times0-6y-18=0&#10;\\-6y=18&#10;\\y=-3<span>

</span>
4 0
3 years ago
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