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trasher [3.6K]
3 years ago
11

Which of the following best describes AgCl

Chemistry
1 answer:
vagabundo [1.1K]3 years ago
7 0

Answer: Where are the answers?

Explanation:

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The atomic number is the number of _____ an atom
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The Rutherford–Bohr model of the hydrogen atom (Z = 1) or a hydrogen-like ion (Z > 1). In this model it is an essential feature that the photon energy (or frequency) of the electromagnetic radiation emitted (shown) when an electron jumps from one orbital to another, be proportional to the mathematical square of atomic charge (Z2). Experimental measurement by Henry Moseley of this radiation for many elements (from Z = 13 to 92) showed the results as predicted by Bohr. Both the concept of atomic number and the Bohr model were thereby given scientific credence. The atomic number is the number of _z_ an atom.
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An industrial chemist is studying a sample of an unknown metal. Describe two ways he could change the metal physically and two w
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Some of the physical changes used by the industrial chemist in order to identify it is by scratching it with other metals in order to find the hardness of it. Trying to deform it in order to find the malleability, and to heat it and measure the temperature in order to find the melting point.  

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2 years ago
What is the molality of a solution if 100.0 g of glucose (C&Hi20e) were dissolved into 750. mL of water?
hodyreva [135]

<u>Answer:</u> The molality of solution is 0.740 m.

<u>Explanation:</u>

To calculate the mass of solvent (water), we use the equation:

Density=\frac{Mass}{Volume}

Volume of water = 750 mL

Density of water = 1 g/mL

Putting values in above equation, we get:

1g/mL=\frac{\text{Mass of water}}{750mL}\\\\\text{Mass of water}=750g

To calculate the molality of solution, we use the equation:

Molarity=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ in grams}}

Where,

m_{solute} = Given mass of solute (C_6H_{12}O_6) = 100.0 g

M_{solute} = Molar mass of solute (C_6H_{12}O_6) = 180 g/mol

W_{solvent} = Mass of solvent (water) = 750 g

Putting values in above equation, we get:

\text{Molality of }C_6H_{12}O_6=\frac{100\times 1000}{180\times 750}\\\\\text{Molality of }C_6H_{12}O_6=0.740m

Hence, the molality of solution is 0.740 m.

6 0
3 years ago
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