Answer:
Technician B.
Explanation:
The claim of technician B that the PCM will add fuel if the IAT indicates that the incoming air temperature is cold is correct.
Answer:
Your answer is cells. Hope this helps!
Hihi!
During Rutherford's experiment<span> of shooting particles through a sheet of </span>gold foil <span>he had discovered that some were deflected! This had proved that an </span>atom<span> is actually a small dense nucleus surrounded by orbiting electrons!
I hope I helped!
-Loliarual</span>
The % error in the second trial is calculated as follows
% error = actual molarity/ theoretical molarity x100
= 0.83/0.95 x100 = 87.4% error of second trial
Pressure is 5.7 atm
<u>Explanation:</u>
P1 = Standard pressure = 1 atm
P2 = ?
V1 = Volume = 10L
V2= 2.4L
T1 = 0°C + 273 K = 273 K
T2 = 100°C + 273 K = 373 K
We have to find the pressure of the gas, by using the gas formula as,

P2 can be found by rewriting the above expression as,

Plugin the above values as,
