Answer:-
(a) 3.5
(b) 3
Explanation:-
2KClO3 --> 2KCl + 3 O2
From the equation we see that 2 moles of KClO3 gives 2 moles of KCl.
So 3.5 moles of KClO3 will give 3 moles of KCl.
Again
3 moles of O2 are produced with 2 moles of KCl.
If 4.5 moles of O2 produced then
moles of KCl = 4.5 x 2/3
=3
Answer : The number of grams of solute in 500.0 mL of 0.189 M KOH is, 5.292 grams
Solution : Given,
Volume of solution = 500 ml
Molarity of KOH solution = 0.189 M
Molar mass of KOH = 56 g/mole
Formula used :

Now put all the given values in this formula, we get the mass of solute KOH.


Therefore, the number of grams of solute in 500.0 mL of 0.189 M KOH is, 5.292 grams
B is the correct answer.
The exosphere is the outermost region of the atmosphere the gradually merges out into space. The water cycle does not occur within this region.
Can you provide a picture
Answer:i read it Explanation: