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Pavlova-9 [17]
3 years ago
7

A nuclear power plant original energy form

Chemistry
1 answer:
Lostsunrise [7]3 years ago
8 0
Jkjhhfibu bugging kidding
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In the combustion of hydrogen gas, hydrogen reacts with oxygen from the air to form water vapor.
Yuliya22 [10]
The balanced chemical equation is:

2H2 + O2 ---> 2H2O

We are given the amount of the product produced from the reaction. This will be the starting point for the calculations.

355 g H2O ( 1 mol H2O/ 18.02 g H2O) ( 1 mol O2 / 2 mol H2O ) ( 32 g O2 / 1 mol O2 ) = 315.205 g O2
6 0
3 years ago
Im sorry if its difficult to read
anzhelika [568]

Answer:

A ball is thrown straight up from a rooftop 320 feet high. The formula below describes the ball's height above the ground, h, in feet, t seconds after it was thrown. The ball misses the rooftop on its way down and eventually strikes the ground. How long will it take for the ball to hit the ground? Use this information to provide tick marks with appropriate numbers along the horizontal axis in the figure shown.

h=-16t^2+16t+320

6 0
3 years ago
Give the theoretical yield, in moles, of CO2 from the reaction of 4.00 moles of C8H18 with 4.00 moles of O2. 2 C8H18(l) + 25 O2(
scoray [572]
2C₈H₁₈ + 25O₂ = 16CO₂ + 18H₂O

n(C₈H₁₈)=4 mol
n(O₂)=4 mol

C₈H₁₈:O₂=2:25 ⇒ 4:50  oxygen is the limiting reagent

n(CO₂)=16n(O₂)/25

n(CO₂)=16*4/25=2.56 mol
6 0
3 years ago
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A sample that contains 4.78 mol of a gas at 251 K has a pressure of 1.19 atm. What is the volume? Answer in units of L.
Y_Kistochka [10]
Answer:
            V  =  81.86 L

Solution:

Data Given;
                   P  =  1.19 atm

                   n  =  4.78 mol

                   T  =  251 K

Let suppose the gas is acting ideally, then according to Ideal Gas Equation,

                                         P V  =  n R T

Solving for V,
                                         V  =  n R T / P

Putting Values,
                             
             V  =  (4.78 mol × 0.0812 L.atm.mol⁻¹.K⁻¹ × 251 K) ÷ 1.19 atm

             V  =  81.86 L
8 0
4 years ago
In the whole earth, the four most common elements (by mass) are oxygen, silicon, magnesium, and ________.
Svetllana [295]
I believe that the answer is iron.
8 0
3 years ago
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