The balanced chemical equation is:
2H2 + O2 ---> 2H2O
We are given the amount of the product produced from the reaction. This will be the starting point for the calculations.
355 g H2O ( 1 mol H2O/ 18.02 g H2O) ( 1 mol O2 / 2 mol H2O ) ( 32 g O2 / 1 mol O2 ) = 315.205 g O2
Answer:
A ball is thrown straight up from a rooftop 320 feet high. The formula below describes the ball's height above the ground, h, in feet, t seconds after it was thrown. The ball misses the rooftop on its way down and eventually strikes the ground. How long will it take for the ball to hit the ground? Use this information to provide tick marks with appropriate numbers along the horizontal axis in the figure shown.
h=-16t^2+16t+320
2C₈H₁₈ + 25O₂ = 16CO₂ + 18H₂O
n(C₈H₁₈)=4 mol
n(O₂)=4 mol
C₈H₁₈:O₂=2:25 ⇒ 4:50 oxygen is the limiting reagent
n(CO₂)=16n(O₂)/25
n(CO₂)=16*4/25=2.56 mol
Answer:
V = 81.86 L
Solution:
Data Given;
P = 1.19 atm
n = 4.78 mol
T = 251 K
Let suppose the gas is acting ideally, then according to Ideal Gas Equation,
P V = n R T
Solving for V,
V = n R T / P
Putting Values,
V = (4.78 mol × 0.0812 L.atm.mol⁻¹.K⁻¹ × 251 K) ÷ 1.19 atm
V = 81.86 L
