Answer:
HCl is the limiting reactant. It will completely be consumed (1.37 moles)
Option D is correct
Explanation:
Step 1: Data given
Mass of Zinc (Zn) = 50.0 grams
Mass of Hydrogen chloride (HCl) = 50.0 grams
atomic mass Zn = 65.38 g/mol
Molar mass HCl = 36.46 g/mol
Step 2: The balanced equation
Zn + 2HCl → ZnCl2 + H2
Step 3: Calculate moles
Moles = mass / molar mass
Moles Zn = 50.0 grams / 65.38 g/mol
Moles Zn = 0.764 moles
Moles HCl = 50.0 grams / 36.46 g/mol
Moles HCl = 1.37 moles
Step 4: Calculate limiting reactant
For 1 mol Zn we need 2 moles HCl to produce 1 mol ZnCl2 and 1 mol H2
HCl is the limiting reactant. It will completely be consumed (1.37 moles)
Zn is in excess. There will react 1.37/2 = 0.685 moles
There will remain 0.764 -0.685 = 0.079 moles
The substance that is a diatomic molecule is B. O2 Oxygen.
Answer:
0.57 M
Explanation:
rate = change in concentration /time
Initial concentration of Cl2O5 = 1.16 M
Let the concentration of Cl2O5 after 5.70 seconds be y
rate = (1.16 - y)/5.7
The reaction follows a first order
Therefore, rate = ky = 0.184y
0.184y = (1.16 - y)/5.7
0.184y × 5.7 = 1.16 - y
1.0488y + y = 1.16
2.0488y = 1.16
y = 1.16/2.0488 = 0.57 M
Concentration of Cl2O5 after 5.70 seconds is 0.57 M
Answer:it’s C
Explanation:
A distant luminous object travels rapidly away from an observer.
Answer:The correct answer is option (C).
Explanation:
After the reaction between Zinc and copper(II) chloride, Zinc chloride and copper will be obtained as a product. This reaction occurs because zinc is more reactive than copper which displaces the copper from its aqueous solution.
The student will expect to find copper metal at bottom of the beaker with aqueous solution of zinc chloride.
Hence the correct answer is option (C).
