A sample that contains 4.78 mol of a gas at 251 K has a pressure of 1.19 atm. What is the volume? Answer in units of L.
1 answer:
Answer:
V = 81.86 L
Solution:
Data Given;
P = 1.19 atm
n = 4.78 mol
T = 251 K
Let suppose the gas is acting ideally, then according to Ideal Gas Equation,
P V = n R T
Solving for V,
V = n R T / P
Putting Values,
V = (4.78 mol × 0.0812 L.atm.mol⁻¹.K⁻¹ × 251 K) ÷ 1.19 atm
V = 81.86 L
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