In a solution of water and salt,which substance is the solute?

Chemistry

2 answers:

hoa [83]3 years ago

4 0

Salt is the solute. :)

mart [117]3 years ago

4 0

The water is the solute since its a liquid and salt is dissolved in the water

You might be interested in

What happens to iron oxide during decomposition

elena55 [62]

Answer:

it gets reduced from a +3 oxidation to a 0.

Explanation:

the decomposition of iron oxide to elemenTal can be represented by the following equation: iron oxide (Fe203), the oxidation state of iron is +3 while that of oxygen is -2. therefore, the above reaction is a redox (reduction oxidation reaction)

4 0

3 years ago

State two reasons why a person might choose a pneumatic system rather than a hydraulic system.

kherson [118]

Answer:

pneumatics are cleaner the system uses no return lines and gases are exhausted to the atmosphere.
efficient and reliable

7 0

3 years ago

what is the best course of action if solid material remains in the flask after the heating step of recrystallization

lys-0071 [83]

Answer:

filter the hot mixture.

Explanation:

Solid is stayed undissolved since the arrangement is gotten super saturated. On the off chance that solid molecule is available recrysallization won't happen in this way we need expel the solid molecule by filtarion in hot condition itself . Subsequently, arrangement become totally homogenous and recrysallization item will shaped by moderate cooling

7 0

4 years ago

How do human obtain the nitrogen they use in their bodies

Komok [63]

Humans get the nitrogen they need by eating vegetebles or other meat that contain nitrogen. hope it helps :)

8 0

3 years ago

RATE LAW QUESTION !

vivado [14]

In general, we have this rate law express.:

$\mathrm{Rate} = k \cdot [A]^x [B]^y$
we need to find x and y

ignore the given overall chemical reaction equation as we only preduct rate law from mechanism (not given to us).

then we go to compare two experiments in which only one concentration is changed

compare experiments 1 and 4 to find the effect of changing [B]
divide the larger [B] (experiment 4) by the smaller [B] (experiment 1) and call it Δ[B]

Δ[B]= 0.3 / 0.1 = 3

now divide experiment 4 by experient 1 for the given reaction rates, calling it ΔRate:

ΔRate = 1.7 × 10⁻⁵ / 5.5 × 10⁻⁶ = 34/11 = 3.090909...

solve for y in the equation $\Delta \mathrm{Rate} = \Delta [B]^y$

$3.09 = (3)^y \implies y \approx 1$

To this point, $\mathrm{Rate} = k \cdot [A]^x [B]^1$

do the same to find x.
choose two experiments in which only the concentration of B is unchanged:

Dividing experiment 3 by experiment 2:
Δ[A] = 0.4 / 0.2 = 2
ΔRate = 8.8 × 10⁻⁵ / 2.2 × 10⁻⁵ = 4

solve for x for $\Delta \mathrm{Rate} = \Delta [A]^x$

$4= (2)^x \implies x = 2$

the rate law is

Rate = k·[A]²[B]

6 0

3 years ago