Answer:
(c) hoping u pass ur grade and stay safe cya
4/12=1/3
8/14=4/7
6/8=3/4
3/6=1/2
5/15=1/3
<u>First what I did was find how much each pound would cost per different package. </u>
<u>So starting off with the 3 pound package. I did 2.49 divided by 3 to find out how much each pound would weigh. </u>
2.49 / 3 = 0 . 83
<u>So each pound in the 3 pounded package would cost $0.83. </u>
<u>Now to see how much the 8 pound package would cost. Just like the 3 pound package I had to find how much each pound would weigh. So I divided 6.49 by 8. </u>
6.49 / 8 = 0.81125
<u>So looking at the results the 3 pound package would be the best option. You are getting more for less. </u>
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HOPES THIS HELPS!
The solution is x=5/4.
We use the properties of logs to rewrite the equation:
![\log[(\frac{x}{2})(\frac{20}{x^2})]=\log8 \\ \\\log(\frac{20x}{2x^2})=\log8 \\ \\\log(\frac{10}{x})=\log8](https://tex.z-dn.net/?f=%5Clog%5B%28%5Cfrac%7Bx%7D%7B2%7D%29%28%5Cfrac%7B20%7D%7Bx%5E2%7D%29%5D%3D%5Clog8%0A%5C%5C%0A%5C%5C%5Clog%28%5Cfrac%7B20x%7D%7B2x%5E2%7D%29%3D%5Clog8%0A%5C%5C%0A%5C%5C%5Clog%28%5Cfrac%7B10%7D%7Bx%7D%29%3D%5Clog8)
Get all of the logs on the same side of the equation y subtracting log 8:

Use the properties of logs to rewrite:

Exponentiate:

Multiply both sides by 8x:
1*8x = (10/8x)*8x
8x=10
Divide both sides by 8:
8x/8 = 10/8
x = 10/8 = 5/4