Question

BMX bicycle rider takes off from a ramp at a point 1.2 m above the ground. The ramp is angled at 40∘ from the horizontal, and the rider's speed is 6.3 m/s when he leaves the ramp.
At what horizontal distance from the end of the ramp does he land?

Express your answer with the appropriate units.

Answer 1

Answer:

The horizontal distance is 5.11 m

Explanation:

please look at the solution in the attached Word file

Download docx

Answer 2

Answer:

The ramp lands at an horizontal distance of 3.989 m

Explanation:

Range: Range is defined as the horizontal distance of a projectile from the point of projection to the point where the projectile hits the projection plane again. It is measure in meters (m)

R = U²sin2∅/g..................................... Equation 1

Where R = The horizontal distance from the end of the ramp, U = rider's speed, ∅ = the ramp's angle to the horizontal.

Given: U = 6.3 m/s, ∅ = 40°, g = 9.8 m/s²

Substituting these values into equation 1

R = [6.3²sin2(40)]/9.8

R = (39.69×sin80)/9.8

R = 39.69×0.985/9.8

R = 3.989 m

Thus the ramp lands at an horizontal distance of 3.989 m