Answer:
The ramp lands at an horizontal distance of 3.989 m
Explanation:
Range: Range is defined as the horizontal distance of a projectile from the point of projection to the point where the projectile hits the projection plane again. It is measure in meters (m)
R = U²sin2∅/g..................................... Equation 1
Where R = The horizontal distance from the end of the ramp, U = rider's speed, ∅ = the ramp's angle to the horizontal.
<em>Given: U = 6.3 m/s, ∅ = 40°, g = 9.8 m/s²</em>
<em>Substituting these values into equation 1</em>
<em>R = [6.3²sin2(40)]/9.8</em>
<em>R = (39.69×sin80)/9.8</em>
<em>R = 39.69×0.985/9.8</em>
R = 3.989 m
Thus the ramp lands at an horizontal distance of 3.989 m