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Neko [114]
3 years ago
10

Which statement describes the effects of forces on an object

Physics
1 answer:
lukranit [14]3 years ago
8 0

Answer:

Sorry this isn’t going to be any help. You don’t have any statement that I’m able to see.

Explanation:

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At the top of the path, the horozontal velocity is___.
Setler [38]

Answer:

the answer is A have a nice day hope I helped

4 0
4 years ago
If a transverse wave osculates 7 times every second and the speed of the wave is 27 m/s what is the wavelength of the wave
Inessa05 [86]

Explanation:

formula is ˠ=vf

f=1/T

1/7

f=0.14

wavelength=27Ⅹ0.14

=3.78m

OR

7Ⅹ27

=189m

5 0
2 years ago
When he reaches the bottom, 4.2 m below his starting point, his speed is 2.2 m/s . By how much has thermal energy increased duri
Advocard [28]

Complete question:

A fireman of mass 80 kg slides down a pole. When he reaches the bottom, 4.2 m below his starting point, his speed is 2.2 m/s. By how much has thermal energy increased during his slide?

Answer:

The thermal energy increased by 3,099.2 J

Explanation:

Given;

mass of the fireman, m = 80 kg

initial position of the fireman, hi = 4.2 m

final speed, v = 2.2 m/s

The change in the thermal energy is calculated as;

ΔE +  (K.Ef - K.Ei) + (Uf - Ui) = 0

where;

ΔE is the change in the thermal energy

K.Ef is the final kinetic energy

K.Ei is the initial kinetic energy

Uf is the final potential energy

Ui is the initial potential energy

\Delta  E_{th} +  (\frac{1}{2} mv_f^2 - \frac{1}{2} mv_i^2) + (mgh_f - mgh_i)=0\\\\initial \ velocity, \ v_i = 0\\final \ height , \ h_f = o\\\\\Delta  E_{th} + (\frac{1}{2} mv_f^2) + ( - mgh_i)=0\\\\\Delta  E_{th} +  \frac{1}{2} mv_f^2 - mgh_i = 0\\\\\Delta  E_{th} =mgh_i  - \frac{1}{2} mv_f^2\\\\\Delta  E_{th} =  80 \times 9.8 \times 4.2  \ \ - \ \ \frac{1}{2} \times 80 \times (2.2)^2  \\\\\Delta  E_{th} = 3292.8 \ J \ - \ 193.6 \ J\\\\\Delta  E_{th} = 3,099.2 \ J

3 0
3 years ago
A sprinter practicing for the 200-m dash accelerates uniformly from rest at A and reaches a top speed of 35 km/h at the 67-m mar
xz_007 [3.2K]

Answer:

0.705 m/s²

Explanation:

a) The sprinter accelerates uniformly from rest and reaches a top speed of 35 km/h at the 67-m mark.

Using newton's law of motion:

v² = u² + 2as

v = final velocity = 35 km/h = 9.72 m/s, u = initial velocity = 0 km/h,  s = distance = 67 m

9.72² = 0² + 2a(67)

134a = 94.484

a = 0.705 m/s²

b) The sprinter maintains this speed of 35 km/h for the next 88 meters. Therefore:

v = 35 km/h = 9.72 m/s, u = 35 km/h = 9.72 m/s, s = 88 m

v² = u² + 2as

9.72² = 9.72² + 2a(88)

176a = 9.72² - 9.72²

a = 0

c) During the last distance, the speed slows down from 35 km/h to 32 km/h.

u = 35 km/h = 9.72 m/s, v = 32 km/h = 8.89 m/s, s = 200 - (67 + 88) = 45 m

v² = u² + 2as

8.89² = 9.72² + 2a(45)

90a = 8.89² - 9.72²

90a = -15.4463

a = -0.1716 m/s²

The maximum acceleration is 0.705 m/s² which is from 0 to 67 m mark.

8 0
3 years ago
A news anchor at a city television station was asked by a rural food bank to speak at its annual fund-raiser. Even though the fu
erma4kov [3.2K]

Answer:

Monitoring reader comments and engagements, mini research about the demographics of previous edition, an online survey

Explanation:

The more she understands the background and need of her audience, the better her speech and coherence will be .

Some ways to discover her audience are:

1. Ask the organizers or do a mini research about the demographics of the audiences that are at the previous edition of the annual fund-raiser. Knowing the demographics such as gender, age group, level of education, language,culture etc. will allow her to Know about the audience's interest ad common grounds.

2. Monitoring of comments and engagements about the program can give her incite about the audience

3. A survey can be carried out if the audience are accessible.

6 0
3 years ago
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