Answer:
1.65
Explanation:
The equation of the forces along the horizontal direction is:
(1)
where
F = 65 N is the force applied with the push
is the frictional force
m = 4 kg is the mass
is the acceleration
The force of friction can be written as (2), where
is the coefficient of kinetic friction
R is the normal force exerted by the floor
The equation of forces along the vertical direction is
(3)
since the bookcase is in equilibrium. Substituting (2) and (3) into (1), we find
And solving for ,
Answer:
c = e > b = d > a
Explanation:
Given vectors are all unit vectors, therefore they have a magnitude of 1
<h3>Let a, b be two vectors and magnitude of cross product of these two vectors is (magnitude of a) × (magnitude of b) × (sine of angle between these two vectors)</h3>
As all are unit vectors their magnitude is 1 and therefore in this case the cross product between any two vectors depends on the sine of angle between those two vectors
In option a as both the vectors are same, the angle between them will be zero and sin0° will also be 0
In option b angle between those two vectors is 135° and sin135° is 1 ÷ √2
In option c angle between those two vectors is 90° and sin90° is 1
In option d angle between those two vectors is 45° and sin45° is 1 ÷ √2
In option e angle between those two vectors is 90° and sin90° is 1
So by comparison of magnitudes of cross products in each option, the order will be c = e > b = d > a
False because when the training higher there is less oxygen
Answer: B) Solid water to liquid water.
Explanation: This would be the melting of water or a transition of solid water to liquid water as energy is added.
Answer:
When he weight of the car is 8.55 x N then power = 314.012 KW
When he weight of the car is 1.10 x N then power = 43.76 KW
Explanation:
Given that
Initial velocity = 0
Final velocity = 24.8
Time = 7.88 sec
We know that power required to accelerate the car is given by
P =
Change in kinetic energy Δ K.E =
Since Initial velocity = 0
⇒ Δ K.E =
⇒ Power P =
⇒ Power P = -------- (1)
(a). The weight of the car is 8.55 x N = 8550 N
Put all the values in above formula
So power P =
P = 314.012 KW
(b). The weight of the car is 1.10 x N = 11000 N
Put all the values in equation (1) we get
P =
P = 43.76 KW