Solve h=vt-gt^2, for v
2 answers:
Answer:
Step-by-step explanation:
As with any "solve for" problem, you undo what has been done to v, in reverse order. In this equation v has been ...
- multiplied by t
- had gt^2 subtracted from the product
So, the first step is to undo the subtraction by adding gt^2 to the equation:
h +gt^2 = vt
Now, we undo the multiplication by dividing by the coefficient of v.
(h +gt^2)/t = v
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Answer option A
From the given graph is a Vertical ellipse
Center of ellipse = (-2,-3)
Vertices are (-2,3) and (-2,-9)
Co vertices are (-6,-3) and (2,-3)
The distance between center and vertices = 6, so a= 6
The distance between center and covertices = 4 , so b= 4
The general equation of vertical ellipse is
(h,k) is the center
we know center is (-2,-3)
h= -2, k = -3 , a= 6 and b = 4
The standard equation becomes
Foci are (h,k+c) and (h,k-c)
Plug in the a=6 and b=4
, we know h=-2 and k=-3
Foci are and
Option A is correct