Answer:
k=14/5
Problem:
Three points have coordinates A (0 , 7) , B (8 , 3) and C (3k , k)
Find the value of the constant k for which C lies on the line that passes through A and B
Step-by-step explanation:
The slope of a line containing points (a,b) and (c,d) is found by computing (b-d)/(a-c). This is just the change in y divided by the change in x.
The slope of a line containing points (0,7) and (8,3) is (7-3)/(0-8)=4/-8=-1/2.
The slope of a line containing points (0,7) and (3k,k) and (8,3) is still -1/2 because it doesn't matter what two points on a line you use to calculate the slope. The slope will remain the same no matter the pair of points on the line you choose for it's calculation.
So lets pretend the question is now find the point (3k,k) such that a line with slope -1/2 goes through (3k,k) and (0,7).
We want to solve the equation:
(k-7)/(3k-0)=-1/2
Simplify denominator
(k-7)/(3k)=-1/2
Cross multiple
(k-7)(2)=(-1)(3k)
Distribute or multiply
2k-14=-3k
Subtract 2k on both sides
-14=-5k
Divide both sufes by -5
-14/-5=k
Simplifying fraction
14/5=k
If an angle is a right angle, its measure is 90.
If an angle measure is 90, the angle is a right angle.
The answer is:
Both statements are true.
This is the biconditional.
An angle is a right angle if and only if its measure is 90°.
Other types of angles:
Acute angle - less than 90°
Obtuse angle - more than 90° but less than 180°.
Straight angle - exactly 180°
Reflex angle - more than 180°
The answer is A
For a function, all you really need to do is plug in any “in” number to the equation to find the “out” number
For example: plugging in 5 into equation 1 would be:
f(5) = 9(5) + 4 = 49
If you keep doing this to each of the other “in” values, you would get the “out” values
Here is the work! The zeros of the graph are at -1 and 3
Use order of operation
Parenthesis
Exponents
Multiply
Divide
Add
Subtract