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marusya05 [52]
3 years ago
11

Write the unit rate as a ratio. Then find an equal ratio There are 7 cheerleaders in a squad. Find the number of cheerleaders on

12 squads
Mathematics
1 answer:
Alex Ar [27]3 years ago
6 0
7/1 cheerleaders per squad
x/12 squads

84 cheerleaders in 12 squads
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B. 21.8°
7nadin3 [17]
Measure of angle is 59.1
7 0
3 years ago
Solve |p + 2|= 10<br> (-12)<br> {-8. 8)<br> {-12, 8)
Firdavs [7]

Answer:

i belive p= 8

Step-by-step explanation:

10-2= 8

8+2 is 10 so p +2 woyld =10

3 0
3 years ago
Can anyone solve it plzzzz ​
Vedmedyk [2.9K]

Answer:

1.A matrix is a rectangular array of numbers, symbols, or expressions, arranged in rows and columns.

2.

Solution given:

We have

Sin²\theta-Cos ²\theta=1

Sin²\theta=1+Cos²\theta

Sin\theta=\sqrt{1-Cos²\theta}

3.

4Tan²\theta+4Cot²\theta-3Tan²\theta-3Cot²\theta

4Tan²\theta-3Tan²\theta+4Cot²\theta-3Cot²\theta

Tan²\theta-Cot²\theta

7 0
3 years ago
1) In a soccer game, the Eagles scored 7 points more than the Cougars. If the Cougars had scored 3 times as many
ira [324]

Answer:

the cougars scored 1 point and the eagles scored 8 points

Step-by-step explanation:

if the cougars would have scored 3 times more points they would have been at which means they scored 1 point because 1x3=3. and if the eagles scores 7 more points than the cougars they would have scored 8 points because 1+7=8.   :)

8 0
3 years ago
The line on the graph passes through the points A (0, 6) and B (3, 0).
Natali5045456 [20]

The equation for the line passing through point A and perpendicular to AB will be y-0.5x=6, the gradient of line AB is -2, and the gradient of a line perpendicular to AB is 0.5.

<h3 /><h3>What is the slope or gradient?</h3>

A numerical assessment of a line's angle relative to the ground is known as the slope.

Given data;

m₁ is the slope of line AB

m₂ is the slope of a line perpendicular to AB

The coordinate points are,

A,(x₁,y₁)= (0, 6)

B,(x₂,y₂)=(3, 0).

The gradient of line AB;

\rm m_{{1} }= \frac{y_2-y_1}{x_2-x_1} \\\\ \rm m_{{1} }= \frac{0-6}{3-0} \\\\ m_{{1} }=-2

The slope of the lines has a perpendicular relation is -1;

m₁ × m₂ = -1

(-2) × m₂ = -1

m₂ = 1/2

m₂ = 0.5

The equation of the line passing through point A and perpendicular to AB;

(y - y₁) = m₂(x-x₁)

(y-6)=0.5(x-0)

y-6 = 0.5 x

y-0.5x=6

Hence, the gradient of line AB, the gradient of a line perpendicular to AB, and the equation of the line passing through point A and perpendicular to AB will be -2,0.5 and y-0.5x=6.

To learn more about the slope, refer to the link;

brainly.com/question/3605446

#SPJ1

4 0
2 years ago
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