a+b+c=9 and a2+b2+c2=35 then by using identity
(a+b+c)2=a2+b2+c2+2ab+2bc+2ca,we get the answer 9x9=35+2(ab+bc+ca)
2(ab+bc+ca)=9x9-35
2(ab+bc+ca) =81-35then we get ab+bc+ca=46/2 so ab+bc+ca=23
I thought they would be the same so I would go with B. 85
The cost function is
c = 0.000015x² - 0.03x + 35
where x = number of tires.
To find the value of x that minimizes cost, the derivative of c with respect to x should be zero. Therefore
0.000015*2x - 0.03 = 0
0.00003x = 0.03
x = 1000
Note:
The second derivative of c with respect to x is positive (= 0.00003), so the value for x will yield the minimum value.
The minimum cost is
Cmin = 0.000015*1000² - 0.03*1000 + 35
= 20
Answer:
Number of tires = 1000
Minimum cost = 20
Answer:
600 x 60 = 36,000
50 x 50 = 2,500
1,000 x 3 = 3,000
70 x 80 = 5,600
100 x 300 = 30,000
20 x 40 = 800
90 x 90 = 8,100
9 x 900 = 8,100
500 x 300 = 150,000
1,000 x 5 = 5,000
125 - 100
770 - 800
364 - 400
923 - 900
755 - 800
Step-by-step explanation:
Answer:
14
Step-by-step explanation:
we can use sin(30⁰) to solve this and the units will be 14
