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3 years ago

Can anyone solve it plzzzz

Mathematics

1 answer:

Vedmedyk [2.9K]3 years ago

7 0

Answer:

1.A matrix is a rectangular array of numbers, symbols, or expressions, arranged in rows and columns.

Solution given:

We have

Sin² $\theta$ -Cos ² $\theta$ =1

Sin² $\theta$ =1+Cos² $\theta$

Sin $\theta$ = $\sqrt{1-Cos²\theta}$

4Tan² $\theta$ +4Cot² $\theta$ -3Tan² $\theta$ -3Cot² $\theta$

4Tan² $\theta$ -3Tan² $\theta$ +4Cot² $\theta$ -3Cot² $\theta$

Tan² $\theta$ -Cot² $\theta$

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A group of college students built a self-guided rover and tested it on a plane surface. They programmed the vehicle to move alon

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Answer:

B. 40 meters

Step-by-step explanation:

— Estimating

The rectangle enclosing the path has sides of length 9 m and 14 m, so its perimeter is 2(9+14) = 46 m. The distance covered will be shorter than that.

The distance from A to C is longer than the distance from D to C, so we know the distance will be longer than 2·14+9 = 37 m.

Only one answer choice fits in the range 37 < d < 46.

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— Detailed calculation

The distance from B to C is the hypotenuse of a right triangle with sides 9 and 12. You will recognize that these side lengths are 3 times the side lengths of a 3-4-5 right triangle, so the hypotenuse distance is 3·5 = 15 meters.

The circuit length is ...

AB +BC +CD +DA = 2 + 15 + 14 + 9 = 40 . . . . meters

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3 years ago

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A family is relocating from St. Louis, Missouri, to California. Due to an increasing inventory of houses in St. Louis, it is tak

Yuri [45]

Answer:

a) Assume that the population has a normal distribution.

And the reason is because this distribution is tabulated and is possible to find quantiles for a confidence level given. And for the uniform distribution we don't have somthing like this.

b) $218- 1.6449 \frac{72}{\sqrt{26}}= 194.77$

$218+ 1.6449 \frac{72}{\sqrt{26}}= 241.23$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X =218$ represent the sample mean

$\mu$ population mean (variable of interest)

$\sigma=72$ represent the population standard deviation

n=26 represent the sample size

Calculate the confidence interval

Part a

For this case the correct answer would be:

Assume that the population has a normal distribution.

And the reason is because this distribution is tabulated and is possible to find quantiles for a confidence level given. And for the uniform distribution we don't have somthing like this.

Part b

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

Since the Confidence is 0.90 or 90%, the value of $\alpha=0.1$ and $\alpha/2 =0.05$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.05,0,1)".And we see that $z_{\alpha/2}=1.6449$