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dalvyx [7]
4 years ago
14

Give main Differences between herbs and Shrbs​

Chemistry
1 answer:
rewona [7]4 years ago
6 0

Answer:"...the different types of plants categorized on the basis of their size and branching pattern. Herbs have soft and unbranched stems, whereas, shrubs have woody, branched and multi stems. Shrubs are often confused with herbs because of their similar characteristics, but shrubs are taller than herbs."   google

Explanation: found on google :) hopes this helps and if not sorry

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Help me now, please!
Nikitich [7]

Answer:

1. SnO2 = 1; H2 = 2; Sn = 1; H2O = 2

2. I mole of SnO2 is required to react with 2 moles of H2 to produce 1 mole of Sn and 2 moles of H20.

The balanced equation represents 1 mole of SnO2

3. Total mass of reactants and products are each 154.71g respectively

Explanation:

1. According to the law of conservation of mass, the total mass of reactants in a chemical reaction is equal to the mass of products.

Therefore, a balanced chemical equation has equal number of moles of each atom on the reactants side and on the product side. The balanced chemical equation for the reaction above will be:

Sn02 + 2H2 + Energy -----> Sn + 2H2O

Sn has 1 mole of atoms on both sides

O has 2 moles of atoms on both sides

H has 4 miles of atoms on both sides.

2. According to the balanced chemical equation above,

1 mole of SnO2 reacts with 2 moles of H2 to produce 1 mole of An and 2 moles of H20.

This balanced equation represents 1 mole of SnO2.

3. The atomic masses of Sn, O and H are 118.71g, 16g and 1g respectively.

Therefore, the molar masses of the reactants and products are;

SnO2 = 118.71 + 16 * 2 = 150.72g

H2 = 2 *1 = 2g

H2O = 2 * 1 + 16 = 18g

Total mass of reactants = 150.71g + 2 * 2g = 154.72g

Total mass of products = 118.71 + 2 * 18g = 154.71g

3 0
3 years ago
If you were helping a friend do stoichiometry problems, what would you tell them about how they might use subscripts and coeffic
Jet001 [13]
Im not sure if this will help but... your subscripts in a balanced equation are used to calculate the molar mass of the compound. And your coefficients are used to get the ratios. so for example we have this balanced equation
Be3N2 + 6H2O= 3Be(OH)2 + 2NH3  and you have to find the molar mass of 6h2o, you need to multiply the subscript by the atomic mass and then add them together to get the overall molar mass.  * 2(1.01) + 16.00= 18.02 g/mol
and if a question wants to know the limiting or excess regent you would use the coefficients to find out the ratio between the compounds.
 
8 0
3 years ago
Read 2 more answers
Why does boron not always continue the period 2 pattern of reacting by losing electrons, as do beryllium and lithium?
gogolik [260]
<span>Elements in Period 2 such as Barium and Beryllium can lose up to two electrons when they react, however Boron can lose up to three electrons when it reacts which causes it to break the pattern normally seen in Period 2.</span>
6 0
3 years ago
Read 2 more answers
Calculate how much carbohydrate a 175-pound athlete who is in training 4-5 hours per day should eat each day in order to enhance
Kamila [148]

Answer:

The athlete should consume about 476 g of carbohydrates per day to maintain a good storage of glycogen in his body

Explanation:

For an athlete who trains daily, 5 to 7 g of carbohydrates per Kg of body weight per day is recommended;

∴ m athlete = (175 Lb)×(0.453592 Kg/Lb) = 79.3787 Kg

⇒ m carbohydrate = (79.3787 Kg)×( 6 g carbohydrate/ Kg.day) = 476.27 g carbohydrate/day

5 0
3 years ago
Lab reaction rate project for chemistry edge2020
guajiro [1.7K]

Answer:

What Affects Reaction Rate?

The purpose of this lab was to see how temperature and particle size affects reaction rate. The first hypothesis is if you increase the temperature of a reaction, then the reaction rate will increase because particles experience more collisions at higher temperatures.The second hypothesis is if you decrease the particle size of a reactant, then the reaction rate will increase because more of the reactants’ molecules will contact each other. The independent variables are particle size and temperature. The dependent variable is reaction rate.

Materials

250 mL graduated cylinder

Thermometer

Water

Timer

Four 250 mL beakers

Seven 1,000 mg effervescent tablets

Two pieces of filter paper

600 mL beaker

Ice

Hot plate

Procedure

Step 1:Gather Materials

Variation of Temperature

Step 2:Measure the Reaction Rate at ≈ 20°C (Room Temperature)

a) Using a graduated cylinder, fill a 250 mL beaker with 200 mL of water.

b) Measure the temperature of the water and record it in the correct row of Table A.

c) Reset the timer. Start the timer as you place a full tablet into the beaker.

d) Record the reaction time on the Data Sheet in the correct row of Table A.

e) Compute the reaction rate to the nearest mg/L/sec. Record it in the last column of Table A. Measure the Reaction Rate at ≈ 40°C

Step 3:Repeat Step 2, heating the water to approximately 40°C using a hot plate during sub-step a. Measure the Reaction Rate at ≈ 65°C

Step 4:Repeat Step 2, heating the water to approximately 65°C using a hot plate during sub-step a. Measure the Reaction Rate at ≈ 5°C

Step 5:Repeat Step 2, chilling the water to approximately 5°C inside an ice bath during sub-step a. (To create an ice bath, place 100 mL of ice and 100 mL of water in a 600 mL beaker of ice water and wait until the temperature reaches approximately 5°C. To save time, you may wish to set up the ice bath, using an additional 250 mL beaker, while working on Step 4.)

Variation of Particle Size

Step 6:Measure the Reaction Rate for a Full Tablet

a) Using a graduated cylinder, fill a 250 mL beaker with 200 mL of water.

b) Reset the timer. Start the timer as you place the tablet in the beaker.

c) Record the reaction time on the Data Sheet in the appropriate row of Table B.

d) Compute the reaction rate to the nearest mg/L/sec. Record it in the last column of Table B.

Step 7:Measure the Reaction Rate for a Partially Broken Tablet

Repeat Step 6, but this time break the tablet into eight small pieces on a piece of filter paper. Make sure to place all of the pieces into the beaker at the same time.

Step 8:Measure the Reaction Rate for a Crushed Tablet

Repeat Step 6, but this time crush the tablet into tiny pieces on a piece of filter paper. Make sure to place all of the pieces into the beaker at the same time.

Step 9: Dispose of all samples according to your teacher’s directions.

Measured Reaction Temperature (°C)

Mass of Tablet (mg)

Volume of Water (L)

Reaction Time (s)

Reaction Rate (mg/L/s)

≈20°C

24

1,000

0.2

34.2

146.2

≈40°C

40

1,000

0.2

26.3

190.1

≈65°C

65

1,000

0.2

14.2

352.1

≈5°C

3

1,000

0.2

138.5

36.1

Relative Particle Size (Small, Medium, Large)

Mass of Tablet (mg)

Volume of Water (L)

Reaction Time (s)

Reaction Rate (mg/L/s)

Full Tablet

large

1,000

0.2

34.5

144.9

Broken Tablet

medium

1,000

0.2

28.9

173.0

Crushed Tablet

small

1,000

0.2

23.1

216.5

The data in the first table show that as the temperature increases the reaction time decreases and in turn the reaction rate increases. The data supported the hypothesis that as temperature increases reaction rate will also increase. The second table shows that as the particle size decreases the reaction time increases because there is more surface area when the particles are smaller. The data in the second table supported the second hypothesis that as particle size decreases the reaction rate will increase because there will be more contact in the molecules. Possible source of error would be an error in stopping the timer in time or chips in the tablets. To improve this lab it could be done with different types of reactions or different temperature or different particle sizes.

Explanation:

6 0
3 years ago
Read 2 more answers
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