CO2 is carbon dioxide which is most famous for being in gas form so i would figure if it was exposed to freezing temperatures it would turn into a liquid then maybe a solid<span />
<span>P*V/T=constant
so P*V= constant*T
if T doesn't change then
P*V= constant
so 150kPa*0.8L=75kPa*xL
xL=150kPa*0.8L/75kPa=1.6L
hope it help</span>
Answer:
-290KJ/mol
Explanation:
ΔHrxn = ΔHproduct - ΔHreactant
ΔHrxn= 4ΔHH3PO4 - {6ΔHH2O + ΔHP4O10}
ΔHrxn = 4(-1279) - [6(-286) - 3110]
= -5116 -(-1716-3110)
= -5116-(-4826)
= -5116 + 4826 = -290KJ/mol
Probably life science or biology.
