Answer: 0.25 moles O in the sample
Explanation:
0.250 moles: C = (0.250 moles)*(12 g/mole) = 3 grams C
0.500 moles H: H = (0.500 moles)*(1 g/mole) = 0.5 grams H
Total mass is 7.5g
Subtract C and H to find grams O (7.5 g -(3 grams C + 0.5 grams H) = 4.0 grams O. Molar mass of O is 16 grams/mole.
Moles O = 0.25 O in the sample
The empirical formula is C1H2O1, possibly formalhyde.
Answer:
Please find the structure attached as an image
Explanation:
Based on the characteristics ending name (-ene) of the organic compound above, it belongs to the ALKENE GROUP. Alkenes are characterized by the possession of a carbon to carbon double bond (C=C) in their structure.
- But-3-ene tells us that the organic compound has four straight carbon atoms with the C=C (double bond) located on the THIRD carbon depending on if we count from right to left or vice versa.
- 2 methyl indicates that the methyl group (-CH3) is located as an attachment on the second carbon (carbon 2).
N.B: In the structure attached below, the counting is from the left to right (→).
Answer: For a. Mass number for the particle is 0.
For b. The charge on the particle is -1.
For c. Another name for 
- particle is electron.
Explanation:
Beta- minus decay is the decay process in which beta-particle is emitted. The mass number of the nuclei remains same and the mass number of the particle is 0. The charge on the particle is -1 and the emitted particle is also called as electron.
For a. The mass number for the particle is 0.
For b. The charge on the particle is -1.
For c. Another name for - particle is electron.
Answer:
F. 2NO + 02 —> 2NO
H. 4NH3 + 502 —> 4NO + 6H20
Explanation:
The law of conservation of mass states that matter can neither be created nor destroyed during a chemical reaction but can be convert from one form to another.
2NO + 02 —> 2NO
From the above, the total number of N on the left balance the total number on the right i.e 2 atoms of N on both side of the equation.
The total number of O on the left balance the total number on the right i.e 2 atoms of O on both side of the equation. This is certified by the law of conservation of mass.
4NH3 + 502 —> 4NO + 6H20
From the above, the total number of N on the left balance the total number on the right i.e 4 atoms of N on both side of the equation.
The total number of O on the left balance the total number on the right i.e 10 atoms of O on both side of the equation.
The total number of H on the left balance the total number on the right i.e 12 atoms of O on both side of the equation.
This is certified by the law of conservation of mass.
The rest equation did not conform to the law of conservation of mass as the atoms on the left side did not balance those on the right side
